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jeyben [28]
3 years ago
6

You invest $5000 at 6.25% interest. How much is in your account after 8 years if

Mathematics
2 answers:
andre [41]3 years ago
8 0
It’s Annually ! So the first answer is correct
romanna [79]3 years ago
6 0

Answer:

A. annually I believe it's the answer bc you add interest every year that way

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Find the length of both of the unknown sides in the triangle shown here.
icang [17]

Answer:

(x+11)^2 = (x+3)^2 +16^2

And if we solve this equation for x we got:

x^2 +22x +121 = x^2 +6x +9 +256

We can cancel x^2 in both sides and we have this:

22x -6x= 256+9-121 =144

And then we got:

16 x= 144

x =\frac{144}{16}= 9

And then the length of the sides are 9+11= 20 m for the hypothenuse, 16 for the adjacent side and 9+3 = 12m for the last side.

Lenght of the smaller unknown side: 12m

Lenght of the larger unknown side: 20m

Step-by-step explanation:

For this case we have a right triangle and we can use the Pythagoras Theorem and using the info given by the triangle we can set up the following equation:

(x+11)^2 = (x+3)^2 +16^2

And if we solve this equation for x we got:

x^2 +22x +121 = x^2 +6x +9 +256

We can cancel x^2 in both sides and we have this:

22x -6x= 256+9-121 =144

And then we got:

16 x= 144

x =\frac{144}{16}= 9

And then the length of the sides are 9+11= 20 m for the hypothenuse, 16 for the adjacent side and 9+3 = 12m for the last side side.

Lenght of the smaller unknown side: 12m

Lenght of the larger unknown side: 20m

8 0
3 years ago
G(x) = -3x + 2 with domain (-1, 2]
Ilia_Sergeevich [38]

Answer:

all real numbers

Step-by-step explanation:

There are no radicals or fractions involved, so the domain is

7 0
3 years ago
) We throw 9 identical balls into 7 bins. How many different ways are there to distribute these 9 balls among the 7 bins such th
ArbitrLikvidat [17]

Answer:

28 ways

Step-by-step explanation:

After placing 1 ball in each of the seven bins, there are two balls left.

If we place both balls in a single bin, there are 7 different ways to place the balls (place both on bins 1 through 7).

If we place each of the remaining balls in a different bin, the number of ways to place the balls is:

n_2=\frac{7!}{(7-2)!2!}=7*3=21

The total number of ways to distribute those balls is 21 + 7 = 28 ways.

3 0
3 years ago
Please answer by today, brainliest will be given when the option is available :)
trasher [3.6K]

Answer:

A: y=2x   :-))

<h2><u><em>HAPPY VALENTINES DAY</em></u></h2>

8 0
2 years ago
Which would be the better buy 5 gallon bucket of paint for $97.45 or 1 gallon bucket of paint for $21.95
Leviafan [203]

Answer:

5 gallons for 97.45

Step-by-step explanation:

5x21.95=109.75 which is more

3 0
3 years ago
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