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777dan777 [17]
3 years ago
5

A baby elephant trots in a straight line along a river. The horizontal position of the elephant in meters over

Physics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

Displacement -6

Distance 24

Explanation:

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30. Light has been described as a ___ and a ___
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Explanation: light has been described as a particle and a wave

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Why is Jupiter's rotation dangerous for human survivability?
krok68 [10]

Answer:

1. Why is Jupiter's rotation dangerous for human survivability?

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2 .Why is Jupiter's planet axis tilt an issue for human survivability?

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3.Why is the diameter of Jupiter an issue for human survivability?

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7 0
2 years ago
A Pitot-static tube is mounted on a 2.5 cm pipe where oil (???? = 860 kg/m3, ???? = 0.0103 kg/m·s) is flowing. The Pitot tube is
emmasim [6.3K]

Answer:

\dot{V}=0.0733 \,m^3.s^{-1}

Explanation:

Given:

density, \rho=860\,kg.m^{-3}

diameter of the pipe, d=2.5\times 10^{-2}m

pressure difference, \Delta P=95.8\times 10^{5}\,Pa

In case of  pitot tube, the velocity is given by:

v=\sqrt{\frac{2.\Delta P}{\rho} }

v=\sqrt{\frac{2\times 95.8\times 10^{5}}{860} }

v=149.26\,m.s^{-1}

Now we know that volumetric flow rate is given as:

\dot{V}=a.v

where :

a= cross sectional area of the pipe

v= velocity of flow

\dot{V}=(\pi\times \frac{(2.5\times 10^{-2})^2}{4} ) \times 149.26

\dot{V}=0.0733 \,m^3.s^{-1}

4 0
3 years ago
What is the Net Force acting<br> on the box below?
Eddi Din [679]
The Net Force would be 2 N to the left.

21 N is being used to push the box to the right and 23 N is used to push it left. There is a stronger force pushing the box towards the left. The different in the two numbers would give you the net force acting on the box and the direction of the arrow with the greatest force will tell you the direction.
4 0
3 years ago
A 1400 kg car drives up a 16 m high hill. The car’s speeds at the bottom and top are 21 m/s and 13 m/s, respectively. If the car
Roman55 [17]

Answer:

Explanation:

mass, m = 1400 kg

height, h = 16 m

initial velocity, u = 21 m/s

final velocity, v = 13 m/s

Work done by engine, We = 80 kJ

Let the work done by the friction force is Wf.

Use the work energy theorem

net work done = change in kinetic energy

work done by engine + work done by friction force + work done by the gravitational force = Change in kinetic energy

80000 + Wf - m x g x h = 0.5 m ( v² - u²)

80000 + Wf - 1400 x 9.8 x 16 = 0.5 x 1400 x ( 169 - 441 )

- 139520 + Wf = - 190400

Wf = 50880 J

4 0
3 years ago
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