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Natasha_Volkova [10]
3 years ago
5

A plane that is 2000m in the air of the potential energy of the plane is 86000 J what is the mass of the plane

Physics
1 answer:
sveticcg [70]3 years ago
6 0

Hi there!

Recall the equation for gravitational potential energy:
GPE = U = mgh

m = mass (kg)
g = acceleration due to gravity (9.8 m/s²)

h = height (m)

We are given the GPE, so we can solve for mass:
86000 = m * 2000 * 9.8

Solve for m:
m = \frac{86000}{2000(9.8)} = \boxed{4.39 kg}

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how long will it take you to travel from rustburg hign school to watch the Devils beat the brookville bees if you live 20 miles
tresset_1 [31]

(20 miles) x ( 1/45  hour/mile) = 

       (20/45) (hour) = <em>

         4/9  hour =    </em>
26 minutes  40 seconds


7 0
3 years ago
The current in the wires of a circuit is 120.0 milliamps.If the voltage impressed across the ends of the circuit where tripled(w
ivanzaharov [21]

Answer:

Explanation:

Current in a wire is 120mA

I = 120mA = 120 × 10^-3 A

I = 0.12 A

If the voltage applied at across the wire is tripled

From ohms law

V=IR

R = V / I

Since R is constant

Then,

V / I = K

Then, we can say

V / I = V' / I'

Given that,

Initially

V = V and I = 120mA

Then, V' = 3V and I' =?

So,

V / I = V' / I'

V / 120 = 3V / I'

Cross multiply

V × I' = 120 × 3V

Divide both sides by V

I' = 120 × 3V / V

I' = 360mA

So, the current in the wire when the voltage was tripled is 360mA, the current was also tripled

3 0
4 years ago
You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using e
Mashutka [201]

You are working for a manufacturing company, which is mathematically given as

  • m=3\sqrt{2}
  • m=\frac{15\sqrt{5}}{16}
  • x=0.747a
  • m/n=\frac{(x^2+a^2)3/2}{x^3}

<h3>What is the value of m that will place the movable bead in equilibrium at x-a a ....?</h3>

a)

Generally, the equation for the force of equilibrium is mathematically given as

F=2fcos\theta

Therefore

K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3

m=3\sqrt{2}

b)

By force equilibrium

K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}

Therefore

n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\

m=\frac{15\sqrt{5}}{16}

c)

K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}

x^2+a^2=(14/3)^{2/3}x^2

x=a/1.338

x=0.747a

d)

By force equilibrium

K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}

m/n=\frac{(x^2+a^2)3/2}{x^3}

Read more about electric fields

brainly.com/question/9383604

#SPJ1

3 0
2 years ago
The greatest number of thunderstorms occur in the _____.
Agata [3.3K]
The appropriate response is tropics. Rainstorms happen when there is warm air that ascents. This air should likewise be clammy or saturated. Hence, regions that are warm and moist are typically where rainstorms happen. (These spots are most generally found around the equator)
8 0
3 years ago
Read 2 more answers
on the surface of planet x, a body with a mass of 10 kilograms weighs 40. newtons. the magnitude of the acceleration due to grav
VARVARA [1.3K]
Based on the Newton's second law of motion, the value of the net force acting on the object is equal to the product of the mass and the acceleration due to gravity. If we let a be the acceleration due to gravity, the equation that would allow us to calculate it's value is,

      W = m x a

where W is weight, m is mass, and a is acceleration. Substituting the known values,

    40 kg m/s² = (10 kg) x a

Calculating for the value of a from the equation will give us an answer equal to 4. 

ANSWER: 4 m/s². 
7 0
3 years ago
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