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2 years ago

A particle travels in a circle of radius 14 m at a constant speed of 21 m/s. What is the magnitude of the acceleration (in m/s2)

Physics

1 answer:

Salsk061 [2.6K]2 years ago

4 0

The magnitude of the acceleration is equal to 31.5 $m/s^2$

<u>Given the following data:</u>

Radius = 14 meters.

Speed = 21 m/s

To determine the magnitude of the acceleration:

In Science, the acceleration of a particle in a <u>circle</u> or circular track is known as centripetal acceleration.

<h3>How to calculate centripetal acceleration.</h3>

Mathematically, centripetal acceleration is given by this formula:

$a = \frac{V^2}{r}$

Substituting the given parameters into the formula, we have;

$a = \frac{21^2}{14}\\\\a=\frac{441}{14}$

Centripetal acceleration = 31.5 $m/s^2$

Read more on centripetal acceleration here: brainly.com/question/25780931

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