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Ratling [72]
2 years ago
14

A particle travels in a circle of radius 14 m at a constant speed of 21 m/s. What is the magnitude of the acceleration (in m/s2)

Physics
1 answer:
Salsk061 [2.6K]2 years ago
4 0

The magnitude of the acceleration is equal to 31.5 m/s^2

<u>Given the following data:</u>

  • Radius = 14 meters.
  • Speed = 21 m/s

To determine the magnitude of the acceleration:

In Science, the acceleration of a particle in a <u>circle</u> or circular track is known as centripetal acceleration.

<h3>How to calculate centripetal acceleration.</h3>

Mathematically, centripetal acceleration is given by this formula:

a = \frac{V^2}{r}

Substituting the given parameters into the formula, we have;

a = \frac{21^2}{14}\\\\a=\frac{441}{14}

Centripetal acceleration = 31.5 m/s^2

Read more on centripetal acceleration here: brainly.com/question/25780931

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A person travelled 350 m east from his home and returns back home an hour has displacement of_?​
Svetradugi [14.3K]

Answer:

vector of zero magnitude

Explanation:

The displacement is a vector magnitude, therefore, in addition to being a module, it has direction and sense.

In this case it moved 350 m and then returned the same 350 m, so the total displacement is zero.

If we draw the vector, one has a directional direction to the right and the other direction to the left, therefore when adding the two vectors gives a vector of zero magnitude

7 0
2 years ago
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Natalka [10]
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7 0
3 years ago
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A 1100 kgkg safe is 2.4 mm above a heavy-duty spring when the rope holding the safe breaks. The safe hits the spring and compres
Drupady [299]

Answer:

191.36 N/m

Explanation:

From the question,

The Potential Energy of the safe = Energy of the spring when it was compressed.

mgh = 1/2ke²............... Equation 1

Where m = mass of the safe, g = acceleration due to gravity, h = height of the save above the heavy duty spring , k = spring constant, e = compression

Making k the subject of the equation,

k =2mgh/e²................ Equation 2

Given: m = 1100 kg, h = 2.4 mm = 0.0024 m, e = 0.52 m

Constant: g = 9.8 m/s²

Substitute into equation 2

k = 2(1100)(9.8)(0.0024)/0.52²

k = 51.744/0.2704

k = 191.36 N/m

Hence the spring constant of the heavy-duty spring = 191.36 N/m

3 0
2 years ago
A stone is dropped from a bridge and hits the pavement below in two seconds. What is the velocity of the stone when it hits the
Helen [10]
We have: a = v/t
Here, t = 2 s  [ Given ]
a = 9.8 m/s²  [constant value for earth system ]

Substitute their values into the expression:
9.8 = v/2
v = 9.8 × 2
v = 19.6 m/s

In short, Your Answer would be Option B

Hope this helps!
4 0
3 years ago
Read 2 more answers
To provide the pulse of energy needed for an intense bass, some car stereo systems add capacitors. One system uses a 2.4F capaci
Natasha_Volkova [10]

Answer:

Explanation:

Energy stored in a capacitor

= 1/2 CV²

C is capacitance and V is potential of the capacitor .

When capacitor is charged to 24 V ,

E₁ = 1/2 x 2.4 x 24 x24 = 691.2 J

When it is charged to 12 volt

E₂ = 1/2 CV²

.5 X 2.4 X 12 X12

= 172.8 J

3 0
3 years ago
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