Question

A particle travels in a circle of radius 14 m at a constant speed of 21 m/s. What is the magnitude of the acceleration (in m/s2)

Answer 1

The magnitude of the acceleration is equal to 31.5 $m/s^2$

Given the following data:

• Radius = 14 meters.

• Speed = 21 m/s

To determine the magnitude of the acceleration:

In Science, the acceleration of a particle in a circle or circular track is known as centripetal acceleration.

How to calculate centripetal acceleration.

Mathematically, centripetal acceleration is given by this formula:

$a = \frac{V^2}{r}$

Substituting the given parameters into the formula, we have;

$a = \frac{21^2}{14}\\\\a=\frac{441}{14}$

Centripetal acceleration = 31.5 $m/s^2$

Read more on centripetal acceleration here: brainly.com/question/25780931