Determine the molecular formula for a compound that has a Mass of 392.2 grams and consists of 0.70g of chromium,0.65g of sulfur
1 answer:
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Explanation:
The given data is as follows.
Concentration = 0.1
= 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions
=
T = = (30 + 273) K = 303 K
Formula for electric double layer thickness () is as follows.
=
where, = concentration =
Hence, putting the given values into the above equation as follows.
=
=
= m
or, =
= 1 nm (approx)
Also, it is known that =
Hence, we can conclude that addition of 0.1 of KCl in 0.1
of NaBr "
" will decrease but not significantly.
Answer:
295.7 mL of 24% trichloroacetic acid (tca) is needed .
Explanation:
Let the volume of 24% trichloroacetic acid solution be x
Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces
= 24 ounces = 709.68 mL
(1 ounces = 29.57 mL)
Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.
x = 295.7 mL
295.7 mL of 24% trichloroacetic acid (tca) is needed .