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Elden [556K]
3 years ago
13

Determine the molecular formula for a compound that has a Mass of 392.2 grams and consists of 0.70g of chromium,0.65g of sulfur

and 1.30 grams of oxygen​
Chemistry
1 answer:
babunello [35]3 years ago
4 0

Explanation:

yuyfjkvg8hvcrnkffhbbbvvggh

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3. If the percent by volume is 2.0% and the volume of solution is 250 mL, what is the volume of solute in solution? (1 point) 0.
igor_vitrenko [27]
Volume percent = Volume of solute
                              ----------------------------------
                                Volume of the solution
  
                  2                    Volume of the solute
               -------   =           ------------------------------
                100                               250
                     
         Volume of the solute = 2 x 250
                                                ------------
                                                  100         

                                             =   5 mL.

Hope this helps!




                            




4 0
3 years ago
For each set of reactions, determine the value of δh2 in terms of δh1. a+b→2c,δh1 1/2a+1/2b→c,δh2=? express your answer in terms
allochka39001 [22]
ΔH2 = - δH1 δH2 = - 2 x δH1 δH2 = 2 x <span>δ</span>H1
3 0
3 years ago
C. Neither a Physical or Chemical Changu
Nutka1998 [239]

Explanation:

I think B a chemical change

5 0
3 years ago
What is the mass of insoluble lead(II) iodide (461.0 g/mol) produced from 0.830 g of potassium iodide (166.00 g/mol) and aqueous
VikaD [51]

Answer:

C

Explanation:

7 0
3 years ago
If 3.89 × 1024 atoms of a noble gas is collected and it has a mass of of 848 grams, this element is most likely a. He b. Ne c. A
bearhunter [10]

Answer:

Xenon

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Avogadro constant:-

N_a=6.023\times 10^{23}

Let the molar mass of the element is x g/mol

So,

6.023\times 10^{23} atoms have a mass of x g

Also,

3.89\times 10^{24} atoms have a mass of \frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24} g

This mass is equal to 848 g

So,

\frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24}=848

x= 131.3 g/mol

This mass correspond to xenon.

3 0
3 years ago
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