Answer:
The product of the pressure and volume.
Answer:
number of protons: 94
number of neutrons: 145
239
Pu
94
Explanation:
1) The atomic number, Z, of plutonium is Z = 94, i.e plutonium 94 protons
2) Plutoniun-239 is the isotope with mass number 239.
3) Mass number = number of protons + number of neutrons =>
number of neutrons = mass number - number of protons = 239 - 94 = 145
4) The notation requires that you indicate the symbol of the element with the atomic number (number of protons) and the mass number.
You put the mass number as a superscript at the left side of the symbol and the atomic number as subscript to the left of the symbol.
So, in this case the symbol is Pu, the superscript to the left is 239 and the subscript to the left is 94.
239
Pu
94
Answer:
B one mole of carbon is lighter than one mole of magnesium
Boric acid, H3BO3, in aqueous solution would only give out one H+ ion. As it is also produce OH ion and by hydrolysis it produces one proton. <span>All the boron compounds (BX3) are having only 6 valence electrons in it and should follow the octet rule by taking another electron.</span>
B(OH)3 + 2 H2O → B(OH)4− + H3O
Answer:
Percent ionic character of HI bond is 4.91%.
Explanation:
<h3>
Given Data:</h3>
Measured Dipole = 0.380D
bond distance = d = 161pm = 1.61*10^-8 cm
<h3>
Calculation:</h3>
% ionic character is determined by following equation:
% ionic= (dipole measured/dipole calculated)*100
Now,
(In above step 3*10^8 is multiplied to convert coulomb into esu)
As,
So,
Now we can % ionic character using above equation:
%ionic=(0.380D/7.728D)*100
% ionic character=4.91%
