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Ghella [55]
4 years ago
14

Fog is an example of solution collide suspension

Chemistry
2 answers:
solniwko [45]4 years ago
6 0
Collide I am pretty sure :)
IrinaVladis [17]4 years ago
4 0
I'd say it's suspension, but I'm not 100% sure...

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Determine the amount in grams needed to produce a solution of 2.50 M NaOH in 2.00 L.
creativ13 [48]

Answer:

200 g of NaOH

Explanation:

For this solution of NaOH

2.50 M means that in 1L of solution, we have 2.5 moles

Mol . molar mass = Mass

2.5 m  .  40 g/m = 100 grams

In 1 L, we have 100 grams of solute, so in 2L, we have the double

200 g of NaOH

3 0
4 years ago
_________ refers to the total energy of a system.
inna [77]
    Enthalpy refers to the total energy of a system. Hope this helped!
3 0
4 years ago
Read 2 more answers
A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne
Ymorist [56]

Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

P = 5.7 × 10⁻³ atm

Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

mHe = 0.52 mg = 0.52 × 10⁻³ g

mNe = 2.05 mg = 2.05 × 10⁻³ g

The molar mass of He is 4.00 g/mol. The moles of He are:

0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 2.5 × 10⁻³ atm

The total pressure is the sum of the partial pressures.

P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm

6 0
3 years ago
Mercury-203 undergoes beta minus decay. 203 80 hg → 203 81 tl ? the subatomic particle produced is a(n) . 203 80 hg → 203 81 tl
cricket20 [7]

The correct balanced equation of a beta decay undergone by Mercury-203 is as follows:

203 80 Hg → 203 81 + 0 -1 e

<h3>What is beta decay?</h3>

Beta decay in radioactivity refers to the release of a beta particle by a radioactive element.

Beta particle is characterized by the possession of mass number 0 and atomic number -1.

This means that if Mercury-203 undergoes beta decay, the atomic number of the resulting isotope will be +1 as follows:

203 80 Hg → 203 81 Tl + 0 -1 e

Learn more about beta radiation at: brainly.com/question/1580990

8 0
2 years ago
What is the formula for finding the density of<br> an object?
TEA [102]
The answer would be:
D = M/V

D=Density
M= mass
V= volume
3 0
4 years ago
Read 2 more answers
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