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Zarrin [17]
2 years ago
15

Please help 19.0 kg/0.021 m^3

Chemistry
1 answer:
irina1246 [14]2 years ago
6 0

Answer:

904.8 kg / m3

Explanation:

19.0 kg/0.021 m^3 = 904.761905 kg / m3

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What is the molarity of a solution that contains 87.75g of NaCI in 500.ml of solution
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Answer:

M = 3.0 mol/L.

Explanation:

  • We can calculate the molarity of a solution using the relation:

<em>M = (mass x 1000) / (molar mass x V)</em>

  • M is the molarity "number of moles of solute per 1.0 L of the solution.
  • mass is the mass of the solute (g) (m = 87.75 g of NaCl).
  • molar mass of NaCl = 58.44 g/mol.
  • V is the volume of the solution (ml) (V = 500.0 ml).

∴ M = (mass x 1000) / (molar mass x V) = (87.75 g x 1000) / (58.44 g/mol x 500.0 ml) = 3.0 mol/L.

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Explanation:

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A decrease is the concentration of nitrogen monoxide (blank#1) between NO and H2 molecules. The rate of the forward reaction the
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In the given situation, the reaction is-

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Now, if the concentration of NO is decreased there will be fewer molecules of the reactant NO which would decrease the its collision with H2. As a result the rate of the forward reaction would also decrease.

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