The answer = 6.3 × 10-2
(scientific notation)
= 6.3e-2
(scientific e notation)
= 63 × 10-3
(engineering notation)
(thousandth; prefix milli- (m))
= 0.063
<span>(real number)</span>
The score of 96 is 2 standard deviations above the mean score. Using the empirical rule for a normal distribution, the probability of a score above 96 is 0.0235.
Therefore the number of students scoring above 96 is given by:
Answer:
-7.14
Step-by-step explanation:
Evaluate
−4.2(−2.8 + 4.5)
Open parenthesis
(-4.2 * -2.8) + (-4.2 * 4.5)
= (11.76) + (- 18.9)
= 11.76 - 18.9
= -7.14
NOTE:
Negative (-) × negative (-) = positive (+)
Positive (+) × positive (+) = positive (+)
Negative (-) × positive (+) = negative (-)
Positive (+) × negative (-) = negative (-)
The function:
f ( x ) = x * 0.965^t
where x is the initial amount and t is the number of the years
80 = x * 0.965^3
80 = x * 0.89632
x = 80 : 0.89632 ≈ 89
Answer:
The initial amount of animals was 89.
