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antoniya [11.8K]
3 years ago
10

Need help ASAP please

Mathematics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

i think its A im not sure

Step-by-step explanation:

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Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel
Airida [17]

Answer:

89.1° or -1.4°  

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

(3) \, t =\dfrac{2}{\cos \theta}

Substitute (3) into (2)

-50 = 600t \sin \theta - 4.9t^{2} =  600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )

Set up a quadratic equation

\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0
3 years ago
PLEASEHELP!!!!!!
pantera1 [17]

Using proportions, it is found that the speed of the runners are of 16 mph and of 20 mph.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount.

After 30 minutes, the runners are 2 miles apart, hence the second runner is 4 miles per hour faster than the second, that is:

v_2 = v_1 + 4.

The first runner's speed is 4/5 of the speed of the second runner, hence:

v_1 = \frac{4}{5}v_2

v_1 = \frac{4}{5}(v_1 + 4)

\frac{1}{5}v_1 = \frac{16}{5}

v_1 = 16

v_2 = 16 + 4 = 20

Hence, the speed of the runners are of 16 mph and of 20 mph.

More can be learned about proportions at brainly.com/question/24863377

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WARRIOR [948]

Answer:

f(x) = 0.5(x + 3)^2 + 5.

Step-by-step explanation:

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f(x) = 0.5x^2

Now a shift of 3 to the left  gives f(x) = 0.5(x + 3)^2.

5 units up gives 0.5(x + 3)^2 + 5.

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