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3 years ago

Alcohol and water have different boiling points. Which method would you use to separate them

Chemistry

2 answers:

zheka24 [161]3 years ago

5 0

Answer:

Distillation.

Explanation:

Distillation is the separation technique which can be used for separation of any two liquids of different boiling points.

The boiling point of water is near 100 degree celsius while that of alcohol is less than it.

So if we separate them with distillation, then alcohol will separate out first.

If two liquids have close boiling points then we can use fractional distillation.

eimsori [14]3 years ago

3 0

Distillation method would be a good method.

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Calculate the ph of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions.

Makovka662 [10]

The pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.

pH is defined as the concentration of the hydrogen bond which is released or gained by the species in the solution which depicts the acidity and basicity of the solution.

pOH is defined as the concentration of the hydronium ion present in solution.

pOH value is inversely proportional to the value of pH.

pH value increases, pOH value decreases and vice versa.

Given,

Total H+ ions = 2.95 ×10^(-12)M

<h3>Calculation of pH</h3>

pH = -log[H+]

By substituting the value of H+ ion in given equation

= log(2.95× 10^(-12) )

= 13.5

Thus we find that the pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.

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What is the solution of Ag + Cu2+ --> ?

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3 years ago

A sub-shell with n = 6, l = 2 can accommodate a maximum of:

Mrrafil [7]

Answer:

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3 years ago

Compare The atomic number

gayaneshka [121]

Answer:

They are different ions of the same element.

Explanation:

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Balance the following reactions using either the oxidation number method or the half-reaction method. Identify which element has

Marina86 [1]

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$ is the balanced chemical equation.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.

Half-reaction method:

Unbalanced chemical equation:

$Ce^{4+} + I^-$ → $Ce^{3+} + IO^{3-}$

Oxidation half-reaction:

$I^-+ 6OH^- - 6e-$ → I $O^{3-} + 3H_2O$

Reduction half-reaction:

$Ce4^+ + e^-$ → $Ce^{3+}$

Balanced chemical equation:

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO^{3-} + 3H_2O$

Oxidation number method:

Unbalanced chemical equation:

$Ce^{4+} + I^-$ → $Ce^{3+} + IO^{3-}$

$I^{-1} -6e^-$ → $I^{+5}$

$Ce^{4+} + e^-$ → $Ce^{3+}$

Balanced chemical equation:

$6Ce^{4+} + I^{-1}$ → $6Ce^{3+} + I^{+5}$

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$

Hence, $6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$ is the balanced chemical equation.

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