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2 years ago

A relation includes the coordinate (3,3). What other coordinate must be included in the relation if it is even?

1 answer:

3 0

let's not forget that when a relation is "even" f(-x) = f(x), or namely any negative of "x" yields the same result as any positive one.

if this relation is "even" and has (3 , 3), where x = 3, then if we were to plug f(-3) we should get a result or y-value of the same 3, giving us a point of (-3 , 3).

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Brrunno [24]

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If Belinda wants to earn AT LEAST $400 profit (money earned after her expenses), how many pies does she need to sell?

Monica [59]

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2 years ago

Translate into an algebraic expression: If I travel d miles in h hrs downstream on a river with a current of c mph, what would m

xenn [34]

Answer:

The speed is still water is $v = \frac{d}{h} - c$ .

Step-by-step explanation:

Dimentionally speaking, speed is distance divided by time. Since, the person is travelling downstream, absolute speed is equal to the sum of current speed and speed of the person regarding current. Both components are constant. That is:

$c + v = \frac{d}{h}$

Where:

$c$ - Current speed, measured in miles per hour.

$v$ - Speed of the person regarding current, measured in miles per hour.

$d$ - Distance travelled downstream, measured in miles.

$h$ - Time spent on travelling, measured in hours.

Speed in still water occurs when current speed is zero. Then, such variable is obtained after subtracting current speed on both sides of the expression. Hence:

$v = \frac{d}{h} - c$

The speed is still water is $v = \frac{d}{h} - c$ .

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3 years ago

Help me someone!!!!!!!!!!!!!!!!!!!!!!!

Julli [10]

Substitute answers in, a = 3 and b = 2.

(3^2 - 2^2)/(3+2)
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7 0

3 years ago

F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?

Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) = (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

$l_{HF} = \sqrt{\left (4-7 \right )^{2}+\left (1-(-11) \right )^{2}} = \sqrt{\left (-3 \right )^{2}+\left (12 \right )^{2}} = 3\cdot \sqrt{17}$

Similarly, we check the length of HJ, to get;

$l_{HF} = \sqrt{\left (3-7 \right )^{2}+\left (5-(-11) \right )^{2}} = \sqrt{\left (-4 \right )^{2}+\left (16 \right )^{2}} = 4\cdot \sqrt{17}$

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

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3 years ago