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3 years ago

State the type of enthalpy in the followinv equation Koh+Hcl-kcl+h2o ∆h+=-57kj\mol

Chemistry

1 answer:

grandymaker [24]3 years ago

4 0

Answer:

The Enthalpy of neutralization

Explanation:

The reaction of a base (KOH) with an acid (HCl) produce water and its salt (KCl) is called <em>Neutralization Reaction.</em>

This neutralization releases 57kJ/mol.

As the type of enthalpy is due the type of reaction. This enthalpy is:

<h3>The Enthalpy of neutralization</h3>

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3 years ago

A chemist measures the amount of iodine solid produced during an experiment. He finds that of iodine solid is produced. Calculat

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The question is incomplete, the complete question is:

A chemist measures the amount of iodine solid produced during an experiment. He finds that 8.31 g of iodine solid is produced. Calculate the number of moles of iodine solid produced. Round your answer to the correct number of significant digits.

<u>Answer: </u>The number of moles of solid iodine produced is 0.0327 moles

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of solid iodine = 8.31 g

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Plugging values in equation 1:

$\text{Moles of solid iodine}=\frac{8.31g}{253.8089g/mol}=0.0327mol$

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4 years ago

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3 years ago

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Nikitich [7]

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3 years ago

Determine the mass of chloride (MW = 35.45 g/mol ) in grams present in 100 mL of a 0.273 M solution of aqueous FeCl₃ (iron(III)

Naily [24]

Answer:

The mass chloride is 2.903 grams

Explanation:

Step1: calculate the moles of FeCl3

moles = molarity x volume in liters

volume in liters = 100 ml /1000 = 0.1 L

molarity = 0.273 M = 0.273 mol / L

moles = 0.273 mol /L x 0.1 L = 0.0273 moles

step 2: find the moles of Cl

since there is 3 atoms of cl in FeCl3

= 3 x 0.0273 =0.0819 moles

Step 3: calculate mass of cl

mass= moles x molar mass

=0.0819 moles x 35.45 g/mol = 2.903 g

7 0

3 years ago

State the type of enthalpy in the followinv equation Koh+Hcl-kcl+h2o ∆h+=-57kj\mol​

State the type of enthalpy in the followinv equation Koh+Hcl-kcl+h2o ∆h+=-57kj\mol