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Montano1993 [528]
3 years ago
6

State the type of enthalpy in the followinv equation Koh+Hcl-kcl+h2o ∆h+=-57kj\mol​

Chemistry
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

The Enthalpy of neutralization

Explanation:

The reaction of a base (KOH) with an acid (HCl) produce water and its salt (KCl) is called <em>Neutralization Reaction.</em>

This neutralization releases 57kJ/mol.

As the type of enthalpy is due the type of reaction. This enthalpy is:

<h3>The Enthalpy of neutralization</h3>
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PLS I WILL GIVE BRAINLY How do the number of violence electrons of the light metals compared to those heavier than boron
SCORPION-xisa [38]

The valence electron of the light metals are all in the range of 1 to 3.

<h3>What are Valence electron ?</h3>

Valence Electron is the number of electrons in the outer shell of an atom which participate in bond formation.

Number of Valence Electron in Boron is 3 and other light metals lighter than Boron have 1 , 2 of Lithium and Beryllium respectively,

The valence electron of the light metals are all in the range of 1 to 3.

To know more about Valence Electron

brainly.com/question/12717954

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4 0
2 years ago
The hydrogen gas produced is collected over water at 25.0 oC. The volume of the gas is 7.80 L, and the total pressure in the gas
Eva8 [605]

Answer:

20.4 grams Zn

Explanation:

To find the mass, you first need to find the moles. This can be found using the Ideal Gas Law equation:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

Before you can plug the values into the equation, you need to convert Celsius to Kelvin.

P = 0.980 atm                   R = 0.08206 atm*L/mol*K

V = 7.80 L                          T = 25.0 °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(0.980 atm)(7.80 L) = n(0.08206 atm*L/mol*K)(298.15 K)

7.644 = n(24.466)

0.312 moles = n

Now that you have the number of moles, you can convert it to grams using the atomic mass of zinc. The final answer should have 3 sig figs to match the sig figs in the given values.

Atomic Mass (Zn): 65.380 g/mol

0.312 moles Zn           65.380 grams
-------------------------  x  -------------------------  =  20.4 grams Zn
                                         1 mole

5 0
2 years ago
Explain why you get a basic solution when you dissolve NaF in water.
SashulF [63]

Answer:

<em>That's </em><em>because</em><em> </em><em>in </em><em>water</em><em> </em><em>NaF </em><em>will </em><em>dissolve</em><em> </em><em>to </em><em>produce </em><em>Na</em><em>+</em><em>,</em><em>the </em><em>conjugate </em><em>base </em><em>of </em><em>a </em><em>strong</em><em> </em><em>acid </em><em>which</em><em> </em><em>will </em><em>not </em><em>react </em><em>with </em><em>water.</em><em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em> </em><em>F- </em><em>will </em><em>behave </em><em>like </em><em>a </em><em>bronsted </em><em>base,</em><em> </em><em>and </em><em>accept</em><em> </em><em>a </em><em>proton </em><em>from </em><em>water.</em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>is </em><em>called </em><em>hydrolysis</em><em> </em><em>reaction,</em><em> because</em><em> </em><em>a </em><em>molecule</em><em> </em><em>of </em><em>water </em><em>is </em><em>broken </em><em>up.</em>

<em>a </em><em>conjugate</em><em> base</em><em> </em><em>is </em><em>what </em><em>I </em><em>leftover </em><em>after </em><em>an </em><em>acid </em><em>loses </em><em>a </em><em>hydrogen</em><em> </em><em>ion.</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

5 0
3 years ago
The number of neutrons and protons in the nuclei of two atom A and B is as follow: [A] proton= 8 and neutron = 8, [B] proton = 8
sveticcg [70]
A.atomic mass(a)=16
atomic mass(b)=18
b.a and b are isotopes
c.(a)=2,6
(b)=2,6
4 0
3 years ago
Assume that 12.0 g of oxygen are reacted with 20.0 g of magnesium to produce magnesium oxide.
FinnZ [79.3K]
Write out the eqn of magnesium and oxygen. this should be under “metals” chapter. do revise.

next, find the mols of both oxygen and magnesium. compare the ratios and find the LIMITING REAGENT.

use the mols of the limiting reagent to compare with the mols of the product.

take the mols of the product/mr of the product.

this will give u the mass.
8 0
3 years ago
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