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MAVERICK [17]
3 years ago
7

Can someone help me with all of those pls!!!!

Chemistry
1 answer:
Nina [5.8K]3 years ago
4 0
1. Rotates
2. Solar eclipse
3. You can sometimes
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PLEASE HELP ME!!!!!
Oxana [17]
The second one is correct im pretty sure
3 0
4 years ago
Read 2 more answers
What is the wavelength of spectral line resulted from the electron transition from n=3 to n=2 in a hydrogen atom.
MakcuM [25]

Answer:

\lambda=6.56x10^{-7}m

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m

Best regards!

5 0
4 years ago
At what pressure does the mean free path of argon at 20 degrees celsius become comparable to the diameter of a 100 cm3​vessel th
inn [45]

Answer:

The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa

Explanation:

<u>Step 1</u>: Calculate the volume of a spherical container V

V = (4π*r³)/3

r = (3V/4π)^1/3

2r = d = 2*(3V/4π)^1/3

with r= radius

with d= diameter

The diameter is:

d= 2*(3V/4π)^1/3

d= 2*(3*100cm³/4π)^1/3

d= 5.76 cm

<u>Step2 </u>: Define the free path lambda  λ of argon

with  λ =k*T/ σp

with p = kT/σλ

with T= temperature = 20°C = 293.15 Kelvin

with k = Boltzmann's constant = 1.381 * 10^-23 J/K

with p = the atmospheric pressure

with σ = 0.36 nm²

p = kT/σλ

p = (1.38 * 10^-23 J*K^-1 * 1Pa *m³/1J)*(293,15K) /(0.36 nm²*(10^-9/ 1nm)² *(5.76cm* 10^-2m/1cm)

p = 0.195 Pa

The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa

5 0
3 years ago
Use Boyle's Law to solve this problem: A gas has a volume of 10.0 L at a pressure of 4.0 atm. If the gas expands to 20.0 L, what
NARA [144]

Answer:

P₂ = 2 atm

Explanation:

Given data:

Initial volume = 10.0 L

Initial pressure = 4.0 atm

Final volume = 20.0 L

Final pressure = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

4.0 atm × 10.0 L = P₂ × 20.0 L

P₂ = 40.0  atm. L/ 20.0 L

P₂ = 2 atm

7 0
3 years ago
Halp balance plez (⊙◡⊙)
grandymaker [24]

Answer: SnO2 + 2 H2 = Sn + 2 H2O

Explanation: I used a balance equation website. It's called WebQC if you want to check it out for future help.

8 0
3 years ago
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