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kirza4 [7]
3 years ago
7

Why is the study of crime difficult?

Chemistry
2 answers:
Liono4ka [1.6K]3 years ago
8 0
There is no real reason to commit a crime
Bogdan [553]3 years ago
5 0
The study of crime is difficult because there is no real reason to commit a crime
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ioda
Those are basically molecular formula. Which is Table sugar or cane sugar. Generally called sucrose.
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3 years ago
In general, nuclear fusion reactions usually release more energy than nuclear fission reactions.
lisov135 [29]
The answer to your question is: true.

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8 0
3 years ago
Read 2 more answers
Suppose 650.mmol of electrons must be transported from one side of an electrochemical cell to another in 10.0 minutes. Calculate
Alina [70]

Answer:

The size of electric current must 104.5 Ampere.

Explanation:

Moles of electrons = 650 mmol = 650\times 0.001 mol

mmol = 0.001 mol

1 mol =N_A=6.022\times 10^{23} atoms/ions

Number of electrons = N

N = 650\times 0.001\times 6.022\times 10^{23}=3.9143\times 10^{23}

Charge on an electron = 1.602\times 10^{-19} C

Total charge on N electrons = Q

Q=3.9143\times 10^{23}\times 1.602\times 10^{-19} C=62,707.086 C

Duration of time = T = 10 min = 10 × 60 s

1 minute = 60 seconds

Current(I)=\frac{Charge(Q)}{Time(T)}

I=\frac{62,707.086 C}{10\times 60 s}=104.5 A

The size of electric current must 104.5 Ampere.

8 0
3 years ago
A reaction vessel contains 10.0 g of CO and 10.0 g of O2. How many grams of CO2 could be produced according to the following rea
iren2701 [21]

Answer:

1. 15.71 g CO2

2. 38.19 % of efficiency

Explanation:

According to the balanced reaction (2 CO(g) + O2(g) → 2 CO2(g)), it is clear that the CO is the limitant reagent, because for every 2 moles of CO we are using only 1 mole of O2, so even if we have the same quantity for both reagents, not all of the O2 will be consumed. This means that we can just use the stoichiometric ratios of the CO and the CO2 to solve this question, and for that we need to convert the gram units into moles:

For CO:

C = 12.01 g/mol

O = 16 g/mol

CO = 28.01 g/mol

(10.0g CO) x (1 mol CO/28.01 g) = 0.3570 mol CO

For CO2:

C = 12.01 g/mol

O = 16 x 2 = 32 g/mol

CO2 = 44.01 g/mol

We now that for every 2 moles of CO we are going to get 2 moles of CO2, so we resolve as follows:

(0.3570 mol CO) x (2 mol CO2/2 mol CO) = 0.3570 moles CO2

We are obtaining 0.3570 moles of CO2 with the 10g of CO, now lets convert the CO2 moles into grams:

(0.3570 moles CO2) x (44.01 g/1 mol CO2) = 15.71 g CO2

Now for the efficiency question:

From the previous result, we know that if we produce 15.71 CO2 with all the 10g of CO used, we would have an efficiency of 100%. So to know what would that efficiency be if we would only produce 6g of CO2, we resolve as follows,

(6g / 15.71g) x 100 = 38.19 % of efficiency

6 0
3 years ago
What is the formal charge on the xenon atom (xe) in xef2?
Likurg_2 [28]
F  is a    group  17   element  which  are  referred  to  as halogens.  hence  requires  one  electrons   to  obtain  octet    electron  configuration.Therefore F  has  -1  charge.  Xe  is  a  group  18  element  which  are  referred  to  as    noble  gas  which  has  octet  electron  configuration but due  to  the two  F-   Xe   has  +2   formal  charges.
5 0
4 years ago
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