Answer: y = v₀tgθx - gx²/2v₀²cos²θ
a = v₀tgθ
b = -g/2v₀²cos²θ
Step-by-step explanation:
x = v₀ₓt
y = v₀y.t - g.t²/2
x = v₀.cosθt → t = x/v₀.cosθ
y = v₀y.t - g.t²/2
v₀y = v₀.senθ
y = v₀senθ.x/v₀cosθ - g/2.(x/v₀cosθ)²
y = v₀.tgθ.x - gx²/2v₀²cos²θ
a = v₀tgθ → constant because v₀ and θ do not change
b = - g/2v₀²cos²θ → constant because v₀, g and θ do not change
the largest you can have without going over 500 feet is 22.71 in length and 22 in width.
22.71*22=499.62ft
the leftover fence is 0.38ft
hopes this helps
Answer: -23
Step-by-step explanation:
The change in y value can be determined by subtracting the first value from the second.
-19 - 4 = -23
Or if you think about it logically you are going from a positive number to a negative so the total distance will be greater than both of your values.
The total S divided by 8 was 5 more than the if the total S was divided by 10.
So we have S/8 +5 = S/10 and by switching the equation around you get S/10 = S/8+5
The correct answer is B.
Answer:
170 in^2
Step-by-step explanation:
you have to find the area of each surface of the square
1) the square on the right side:
5x5=25 in^2
there are 2 of these on opposite sides
2)the of the rectangle facing us;
6x5=30in^2 (5 because 5 is the height)
there are 4 of these
3)add up all the areas
25+25+30+30+30+30=170in^2
