Methane has the alkane functional group, so the name is composed of meth- for the carbon chain, and –ane for the alkane functional group
Answer:
0.5M
Explanation:
The equation for molarity is:
- M =
; where the "M" stands for molarity, the "mol" stands for moles of solute and the "liters" means the volume in liters of solution.
We are given that there are:
- 1.80 moles of NaCl (the moles of solute)
- 3.60 Liters of solution (the volume in liters of solution)
Now we just plug those numbers into the formula and get our answer:
- M=
= 0.5M
After doing the math and dividing the moles of solute by the liters of solution, we get that the molarity of the solution is 0.5M.
Answer: 143.3
137+115+104+263+98 divided by 5.Which gives us 143.3
The Relative Formula Mass of NaH2PO4 is 120 g/mol
Therefore, the number of moles = 6.6/120
= 0.055 moles of NaH2PO4 which is also equal to the number of moles of H2PO4.
[H2PO4-] = Number of moles oof H2PO4-/Volume of the solution in L
= 0.055/ ( 355 ×10^-3)
= 0.155 M
Na2HPO4 undergoes complete dissociation as follows;
Na2HPO4 (aq)= 2Na+ (aq) + HPO4^2- (aq)
1 mole of Na2HPO4 = 142 g/mol
Therefore; number of moles = 8.0/142
= 0.0563 moles
[HPO4 ^-2] is given by no of moles HPO4^2- /volume of the solution in L
= 0.0563/(355×10^-3)
= 0.1586 M
Both H2PO4^2- and HPO4^2- are weak acids the undergoes partial dissociation
Ka of H2PO4- = 6.20 × 10^-8
[H+] =Ka*([H2PO4-]/[HPO4(2-)]
= (6.20 ×10^-8)×(0.155/0.1586)
= 6.059 ×10^-8 M
pH = - log[H+]
= - log (6.059×10^-8)
= 7.218
