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3 years ago

Of the following gases, ______ will have the greatest rate of effusion at a given temperature.A) NH3B) CH4C) ArD) HBrE) HCl

Chemistry

1 answer:

s344n2d4d5 [400]3 years ago

7 0

Answer:

CH₄

Explanation:

According to Graham's law, <em>the rate of effusion of a gas (r) is inversely proportional to the square root of its molar mass (M)</em>.

Let's consider the following gases and their molar masses.

A) NH₃ 17.03 g/mol

B) CH₄ 16.04 g/mol

C) Ar 39.95 g/mol

D) HBr 80.91 g/mol

E) HCl 36.46 g/mol

Of these gases, CH₄ will have the greatest rate of effusion at a given temperature because it has the lowest molar mass.

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Answer:

Neutral solution is formed.

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We have a solution of NaOH and H₂CO₃

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2 years ago

Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.

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Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

$\%C_E = \frac{E}{T} * 100\%$

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In $(Ca(OH)_2)$

The amount of all elements is: (i.e formula mass of $(Ca(OH)_2)$ )

$T = 1 * Ca + 2 * H + 2 * O$

$T = 1 * 40 + 2 * 1 + 2 * 16$

$T = 74$

The amount of calcium is: (i.e formula mass of calcium)

$E = 1 * Ca$

$E = 1 * 40$

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So, the percentage component of calcium is:

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$\%C_E = \frac{40}{74} * 100\%$

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$\%C_E = 54.05\%$

The amount of hydrogen is:

$E = 2 * H$

$E = 2 * 1$

$E = 2$

So, the percentage component of hydrogen is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{2}{74} * 100\%$

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The amount of oxygen is:

$E = 2 * O$

$E = 2 * 16$

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2 years ago

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