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miss Akunina [59]
3 years ago
9

Im need help please!!!

Mathematics
1 answer:
Arada [10]3 years ago
3 0

Answer:

The measure of the missing angle is 61

Step-by-step explanation:

Using the Consecutive Interior Angles theorem, you know that the angles are supplementary (meaning both angles combine to a 180* plane). Using that logic, you may subtract 119 from 180, and you get a 61* angle.

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Tom has a solid, wooden block that is a rectangular prism with non-square bases. He saws the prism parallel to the base. What sh
Katyanochek1 [597]

Answer:

A) Rectangle

Step-by-step explanation:

Hope this helps :D

6 0
3 years ago
Write in exponent form 85
Nataly [62]

We are given 85

Firstly, we will find all possible factors of 85

we can write it as

85=1*5*17

so, exponential form is

85=5^1*17^1................Answer

4 0
3 years ago
According to the Department of Transportation, 27% of domestic flights were delayed in the last year at JFK airport. Five flight
Mars2501 [29]

Answer:

The probability that all the five flights are delayed is 0.2073.

Step-by-step explanation:

Let <em>X</em> = number of domestic flights delayed at JFK airport.

The probability of a domestic flight being delayed at the JFK airport is, P (X) = <em>p</em> = 0.27.

A random sample of <em>n</em> = 5 flights are selected at JFK airport.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={5\choose x}0.27^{x}(1-0.27)^{5-x};\ x=0,1,2...

Compute the probability that all the five flights are delayed as follows:

P(X=5)={5\choose 5}0.27^{5}(1-0.27)^{5-5}=1\times 1\times 0.207307=0.2073

Thus, the probability that all the five flights are delayed is 0.2073.

4 0
3 years ago
Suppose that a random sample of 10 adults has a mean score of 62 on a standardized personality test, with a standard deviation o
aniked [119]

Answer:

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{4}{\sqrt{10}} = 2.08

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92

The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

5 0
3 years ago
Given the data set (200, 150, 325, 350, 100, 75), Find the range of the data set
andriy [413]
The range is just the distance between the biggest number
and the smallest one.

The biggest number on that list is  350 .
The smallest number on that list is  75 .

The range is from  75 to 350, or a distance of  275 .
4 0
3 years ago
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