The diagram below shows a cone and a cylinder that have congruent bases and congruent heights.

How many years would 18 months be? 1.5 years 1.8 months about 2 years

Luba_88 [7]

Answer:

18 months=1.5 years

Step-by-step explanation:

I hope this helps

7 0

3 years ago

Read 2 more answers

What is the overlap of data set 1 and data set 2 A. High B.moderate C.low D.none

finlep [7]

It's definitely a low data overlap. It's not medium because there's not a solid amount of matching data, and its not 'none' because there is matching data.
so it’s C.

7 0

3 years ago

areas of four triangles are 40 cm^2, 90 cm^2, 202.5 cm^2 and 455.6 cm^2 are continue in sequence. the enlargement factor is 1.5,

maw [93]

Answer:

9th Triangle

Step-by-step explanation:

Given the area of four triangles: $40 cm^2, 90 cm^2, 202.5 cm^2 \:and\: 455.6 cm^2$

If the Scale factor is 1.5.

This is a geometric sequence and the common ratio is 1.5 X 1.5.

Therefore, the area of any n triangle can be determined using the function:

$A(n)=40\cdot1.5^{2(n-1)}$

We want to determine which triangle has an area greater than $15000cm^2$ .

When A(n)=15000

$40\cdot1.5^{2(n-1)}>15000\\1.5^{2(n-1)}>\frac{15000}{40} \\1.5^{2(n-1)}>375\\\text{Change to Logarithm form}\\2(n-1)>Log_{1.5}375\\\text{Applying logarithm change of base to base 10 law}\\2(n-1)>\frac{Log 375}{Log 1.5} \\2n-2>14.62\\2n>14.62+2=16.62\\n>8.31$

Therefore, the 9th triangle has an area greater than $15000cm^2$ .

5 0

4 years ago

Which situation is repesented by the graph

forsale [732]

Answer:

answer is A i think im not sure

Step-by-step explanation:

i dont know ask your teacher

4 0

3 years ago

Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab

Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected, and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, $H_0$ : $\mu$ = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, $H_1$ : $\mu$ < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 738.44 hours

s = sample standard deviation = 38.2 hours

n = sample size = 50

So, test statistics = $\frac{738.44-750}{\frac{38.2}{\sqrt{50} } }$ ~ $t_4_9$

= -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0

3 years ago