The answer is 3. As 5 * 3 = 15.
Is there any other equations I may be able to help you with? :)
Explanation:
Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.
According to that Kc is an equilibrium constant in terms of molar concentrations.
and Kc = [C]^c *[D]^d / [A]^a * [B]^b >>>> (1)
in the general reaction:
aA + bB ↔ cC + dD
and, from our balanced equation:
CH4 + H2O ⇔ Co + 3H2 >>> (2)
So, we need to calculate the concentrations (molarity) of the products and reactants:
the Molarity of CH4 = no. of moles/volume (L)
and no. of moles = weigh / Molecular weight = 42.3 / 16 = 2.643 moles
so the molarity of CH4 = 2.643 / 5 = 0.528 molar
the molarity of H20 = (49.2 / 18) / 5 = 0.546 molar
the molarity of CO = (8.32/28) / 5 = 0.059 molar
the molarity of H2 = (2.63 / 2) / 5 = 0.263 molar
By substitution in (1) according to (2);
∴ Kc = [0.059]*[0.263]^3 / ( [0.528]*[0.546]) = 3.7 * 10 ^-3 >>>> (3)
Kp = Kc (RT)^(Δn) >>> (4)
where R is the gas constant = 0.0821,
and Δn is the change in moles in gas= (3(H2) + 1 (CO) - (1 H2O + 1 CH4) = 2
by substition in (4):
∴ Kp = 3.7*10^-3 (0.0821* 1000)^2= 24.939
Answer:
The answer to your question is 2NaCl + 2H₂O ⇒ 2NaOH + Cl₂ + H₂
Explanation:
Original chemical equation
NaCl + H₂O ⇒ NaOH + Cl₂ + H₂
Reactant Element Products
1 Na 1
1 Cl 2
2 H 3
1 O 1
This reactions is unbalanced
2NaCl + 2H₂O ⇒ 2NaOH + Cl₂ + H₂
Reactant Element Products
2 Na 1
2 Cl 2
4 H 4
2 O 2
Now, the reaction is balanced
