Answer:
The correct answer is "Secondary active transport".
Explanation:
Secondary active transport is a form of across the membrane transport that involves a transporter protein catalyzing the movement of an ion down its electrochemical gradient to allow the movement of another molecule or ion uphill to its concentration/electrochemical gradient. In this example, the transporter protein (antiporter), move 3 Na⁺ into the cell in exchange for one Ca⁺⁺ leaving the cell. The 3 Na⁺ are the ions moved down its electrochemical gradient and the one Ca⁺⁺ is the ion moved uphill its electrochemical gradient, because Na+ and Ca⁺⁺are more concentrated in the solution than inside the cell. Therefore, this scenario is an example of secondary active transport.
Answer:
56°
Explanation:
First calculate ![a:](https://tex.z-dn.net/?f=a%3A)
![a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}](https://tex.z-dn.net/?f=a%3D2%20R%20%5Csqrt%7B2%7D%3D2%280.1246%29%20%5Csqrt%7B2%7D%3D0.352%20%5Cmathrm%7Bnm%7D)
The interplanar spacing can be calculated from:
![d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}](https://tex.z-dn.net/?f=d_%7B111%7D%3D%5Cfrac%7Ba%7D%7B%5Csqrt%7B1%5E%7B2%7D%2B1%5E%7B2%7D%2B1%5E%7B2%7D%7D%7D%3D%5Cfrac%7B0.352%7D%7B%5Csqrt%7B3%7D%7D%3D0.203%20%5Cmathrm%7Bnm%7D)
The diffraction angle is determined from:
![\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D%5Cfrac%7Bn%20%5Clambda%7D%7B2%20d_%7B111%7D%7D%3D%5Cfrac%7B1%280.1927%29%7D%7B2%280.2035%29%7D%3D0.476)
Solve for ![\theta](https://tex.z-dn.net/?f=%5Ctheta)
![\theta=\sin ^{-1}(0.476)=28^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Csin%20%5E%7B-1%7D%280.476%29%3D28%5E%7B%5Ccirc%7D)
The diffraction angle is:
![2 \theta=2\left(28^{\circ}\right)=56^{\circ}](https://tex.z-dn.net/?f=2%20%5Ctheta%3D2%5Cleft%2828%5E%7B%5Ccirc%7D%5Cright%29%3D56%5E%7B%5Ccirc%7D)
Answer:
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive ...
Explanation:
braniest
Answer:Rate of change of Velocity per unit time” & definition of Velocity is “Rate of change of Distance per unit Time”. It means that , when acceleration is 0 then , velocity is constant. In short whatever may be the Velocity, if it remains constant then we say that acceleration is zero.
Salt and water
Sugar and salt
Salt and pepper