Answer:
Gold is a metal, more specifically a transition metal, whereas Oxygen is a nonmetal, more specifically a reactive nonmetal. Using this information, you can compare and contrast metals, nonmetals, and metalloids.
Metals are:
Shiny
High melting point
Mostly silver or gray in color
Mostly solids at room temperature – Mercury (Hg) is a liquid at room temperature
Malleable – able to be hammered into a thin sheet
Ductile – able to be drawn/pulled into a wire
Good conductors of heat and electricity
Nonmetals are:
Dull
Low melting point
Brittle – break easily
Not malleable
Not ductile
Poor conductors of heat and electricity
Metalloids are:
Found on the “zig-zag” line on the Periodic Table of Elements
Have properties of both metals and nonmetals
Can be shiny or dull
Semiconductors – able to conduct electricity under certain conditions
Explanation:
Reccomend this site for questions llike these: https://ptable.com/#Properties
Answer:
Molality = <u>10.300 m</u>
<u>Molarity = 6.5970 M</u>
<u>mole fraction = </u>0.156549
Explanation:
39.0 % = ethylene glycol
61.0 % = water
imagine the total mass = 100g
39.0% ethylene glycol = 39g
61.0 % water = 61g
1) Molality = number of moles / mass of solvent (kg)
Molar mass of ethylene glycol = 62.07g/mole
mole = 39g / 62.07g/mole = 0.6283 moles
Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = <u>10.300 m</u>
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<u>2) Molarity</u> = number of moles / volume of solution
Since we know the density of the solution = 1.05g /ml
⇒ volume = 100g / 1.05g /mL = 95.24 mL = 0.09524 L
Molarity = 0.6283 moles / 0.09524 L = <u>6.5970 M</u>
3) Mole fraction
moles water = 61g / 18.02g/mole = 3.38513 moles
Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles
Mole fraction = 0.6283/ 4.0134276 = 0.156549
Answer:
Ka = ( [H₃O⁺] . [F⁻] ) / [HF]
Explanation:
HF is a weak acid which in water, keeps this equilibrium
HF (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + F⁻ (aq) Ka
2H₂O (l) ⇄ H₃O⁺ (l) + OH⁻ (aq) Kw
HF is the weak acid
F⁻ is the conjugate stron base
Let's make the expression for K
K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]
K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]
K . [H₂O] = Ka
Ka, the acid dissociation constant, includes Kwater.
