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Lynna [10]
3 years ago
11

Equation for the for formation of ethanoic acid​

Chemistry
1 answer:
vladimir2022 [97]3 years ago
5 0

Answer:

2 C4H10 + 5 O2 → 4 CH3CO2H + 2 H2O.

Explanation:

Light naphtha components are readily oxidized by oxygen or even air to give peroxides, which decompose to produce acetic acid according to the chemical equation, illustrated with butane .

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Solid solutions that are mixtures of elements with metallic properties are known as_____
marshall27 [118]
Alloys. hope this helps.
4 0
2 years ago
4.How element gold is different from oxygen?
V125BC [204]

Answer:

Gold is a metal, more specifically a transition metal, whereas Oxygen is a nonmetal, more specifically a reactive nonmetal. Using this information, you can compare and contrast metals, nonmetals, and metalloids.

Metals are:

Shiny

High melting point

Mostly silver or gray in color

Mostly solids at room temperature – Mercury (Hg) is a liquid at room temperature

Malleable – able to be hammered into a thin sheet

Ductile – able to be drawn/pulled into a wire

Good conductors of heat and electricity

Nonmetals are:

Dull

Low melting point

Brittle – break easily

Not malleable

Not ductile

Poor conductors of heat and electricity

Metalloids are:

Found on the “zig-zag” line on the Periodic Table of Elements

Have properties of both metals and nonmetals

Can be shiny or dull

Semiconductors – able to conduct electricity under certain conditions

Explanation:

Reccomend this site for questions llike these: https://ptable.com/#Properties

7 0
3 years ago
This question has multiple parts. Work all the parts to get the most points. An aqueous antifreeze solution is 39.0% ethylene gl
nlexa [21]

Answer:

Molality = <u>10.300 m</u>

<u>Molarity = 6.5970 M</u>

<u>mole fraction = </u>0.156549

Explanation:

39.0 % = ethylene glycol

61.0 % = water

imagine the total mass = 100g

39.0% ethylene glycol = 39g

61.0 % water = 61g

1) Molality = number of moles / mass of solvent (kg)

Molar mass of ethylene glycol = 62.07g/mole

mole = 39g / 62.07g/mole = 0.6283 moles

Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = <u>10.300 m</u>

<u />

<u>2) Molarity</u> = number of moles / volume of solution

Since we know the density  of the solution = 1.05g /ml

⇒ volume = 100g / 1.05g /mL   = 95.24 mL = 0.09524 L

Molarity = 0.6283 moles / 0.09524 L = <u>6.5970 M</u>

3) Mole fraction

moles water = 61g / 18.02g/mole  = 3.38513 moles

Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles

Mole fraction = 0.6283/ 4.0134276 = 0.156549

3 0
2 years ago
6547.9 feet to meters<br> Using dimensional analysis
ELEN [110]

Answer:

92.964

Explanation:

8 0
3 years ago
Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain
damaskus [11]

Answer:

Ka = ( [H₃O⁺] . [F⁻] ) / [HF]

Explanation:

HF is a weak acid which in water, keeps this equilibrium

HF (aq)  +  H₂O (l)  ⇄  H₃O⁺ (aq)  +  F⁻ (aq)      Ka

2H₂O (l)  ⇄  H₃O⁺ (l)  +  OH⁻ (aq)   Kw

HF is the weak acid

F⁻ is the conjugate stron base

Let's make the expression for K

K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]

K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]

K . [H₂O] = Ka

Ka, the acid dissociation constant, includes Kwater.

4 0
2 years ago
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