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Annette [7]
3 years ago
6

Cos90degrees cos30 degrees + sec-squared45degrees sin30degrees - cos270degrees sin180degrees

Mathematics
1 answer:
yawa3891 [41]3 years ago
6 0

Step-by-step explanation:

\cos 90 \cos 30 + \sec^2 45 \sin 30 - \cos 270 \sin 180

But we know that

\cos 90 = \cos 270 = \sin 180 = 0

and

\sin 30 = \dfrac{\sqrt{3}}{2} \:\:\text{and}\:\: \sec 45 = \sqrt{2}

so this leaves us with just

\sec^2 45 \sin 30 = (\sqrt{2})^2  \left(\dfrac{\sqrt{3}}{2} \right)= \sqrt{3}

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