6.4 How Many in 2?
2 answers:
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The length of the rectangle is based on its width, so let's call width w and put the length in terms of the width. We are told that the width is 45 less than 4 times the width, so the length is 4w - 45. Area is found by multiplying length times width and we are given the area as 3325. So we will set up length times width and solve for w, which we will then use to solve for l. 3325 = (4w - 45)(w). Multiplying out we have . Move the constant over by subtraction and then we will have a quadratic that can be factored to solve for w.
. We would put that through the quadratic formula to solve for w. When we do that we get that w = 35 and w = -23.75. The 2 things in math that will never EVER be negative is time and distance/length, so -23.75 is out. That means that the width is 35. The length is 4(35) - 45 which is 95. The dimensions of your rectangle are length is 95 and width is 35. There you go!
Answer:
Step-by-step explanation:
To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.
<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.
If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:
a is the height, b is the base, and c is
the hypotenuse.
To obtain the value of the hypotenuse
To find the value of the lenght of the diagonal d across the square, we have:
Where a = b = 20
Substituting the values
Round the answer to 2 decimal places