Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, 
is 37°. We can see from the diagram that 
would be 
143°.
Also, the new bearing is N 25°E. So, 
would be 25°.
Now we can find 
. As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
Step-by-step explanation:
Answer:
The location of a point on the line
Step-by-step explanation:
Generally, we can write an equation in the point slope form as follows;
y-y1 = m(x-x1)
Where m is the slope of the line
So looking at the option, we can easily see that the information we can read directly from the point-slope form is the location of a point on the line.
We can easily tell the value of (x1,y1) which easily gives out the location of that point on the line
Answer:
the number will get 1000 times larger than its original number or 3 zeroes will be added in the last place of the number
Step-by-step explanation:
let's say x=5,
if we multiply 5 by 1000 it becomes 5000 (it is 1000 times more or larger than its orignal number and 3 zeroes are added in 5000).
