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3 years ago

Would you use baking powder to see whether or not it is an acid or a substance? yes/no?

Chemistry

2 answers:

alexandr1967 [171]3 years ago

8 0

Yes you would use it

Zanzabum3 years ago

4 0

Answer:

yes.

Explanation:

If you have a liquid and you want to know if it is acidic, an easy way to tell is to mix in a little baking soda. The baking soda reacts with acids to produce bubbles.

You may be familiar with building a homemade kitchen volcano. You mix vinegar (an acid) with baking soda. It foams up as the baking soda reacts with the acid. This is in essence what you can do to test if a solution is acidic or not. If there is no acid present, the solution will not bubble when you add the baking soda.

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Elements on the current periodic table are organized by what ?

jasenka [17]

Answer:

atomic number

Explanation:

i'm assuming ur in eighth grade, bc same anyway good luck.

7 0

3 years ago

Read 2 more answers

What are the two toxic byproducts of incomplete combustion?

masha68 [24]

Answer:

The answer is option D, that is, carbon and carbon monoxide

8 0

3 years ago

You have 41.6 g of O2 gas in a container with twice the volume as one with CO2 gas in another container. The pressure and temper

prisoha [69]

Answer:

The mass of carbon dioxide is 28.6 grams

Explanation:

Step 1: Data given

Mass of O2 = 41.6 grams

Volume of the O2 container = 2V

Volume of the CO2 container = V

Pressure and temperature are the same

Step 2: Ideal gas law

The ideal gas law = p*V=nRT

For O2: p*2V = n(O2)*R*T

For CO2: p*V = n(CO2)*R*T

n(O2)*R*T / P*2V = n(CO2)*R*T / P*V

Since P, R and T are contstant, we can simplify this to:

n(O2)/2 = n(CO2)

Step 3: Calculate moles of O2

Moles O2 = mass O2/ Molar mass O2

Moles O2 = 41.6 grams / 32 g/mol

Moles O2 = 1.3 mol O2

The number of moles CO2 = 0.65 mol

Mass of CO2 = Moles CO2 * Molar Mass CO2

Mass of CO2 = 0.65 mol * 44.01 g/mol

Mass of CO2 = 28.6 grams

The mass of carbon dioxide is 28.6 grams

5 0

4 years ago

What’s the answer ?

Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

6 0

3 years ago

What ions and/or molecules (apart from water) are present in relatively large proportions in a solution of a weak acid hclo (aq)

matrenka [14]

HClO, perchloric acid is a weak acid. Unlike strong acids like HCl or H2SO4 it not dissociate completely but partially such that an equilibrium exists between the dissociated ions and the undissociated acid. The equilibrium is as shown below:

HClO + H2O ↔ H3O⁺ + ClO⁻

Since HClO is a weak acid, the reverse reaction is favored over the forward reaction. Thus apart from water, HClO will be present in large amounts.

3 0

3 years ago