Answer: 2y = 3x
Reason:
The equation x:y = 2:3 is the same as saying x/y = 2/3
Cross multiply to get 3x = 2y which flips to 2y = 3x
Answer:
Mean
Step-by-step explanation:
Adding up and dividing to find the mean.
We simply add up all of the individual grades, get the total, and then divide by the number of students in the class.
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Answer:
The complete solution is
Step-by-step explanation:
Given differential equation is
3y"- 8y' - 3y =4
The trial solution is

Differentiating with respect to x

Again differentiating with respect to x

Putting the value of y, y' and y'' in left side of the differential equation


The auxiliary equation is




The complementary function is

y''= D², y' = D
The given differential equation is
(3D²-8D-3D)y =4
⇒(3D+1)(D-3)y =4
Since the linear operation is
L(D) ≡ (3D+1)(D-3)
For particular integral

[since
]
[ replace D by 0 , since L(0)≠0]

The complete solution is
y= C.F+P.I

First you must set f (x) =15:
15 = 2x - 5
Now you must solve like a normal equation:
15 = 2x - 5 )+5
20 = 2*x ):2
10 = x
ANSWER: The value of x is 10