Answer:
S = 26.58 meters
Explanation:
Given the following data;
Initial velocity = 4.66 m/s
Acceleration = 5.66 m/s²
Time = 2.35 seconds
To find the distance travelled by the object, we would use the second equation of motion;
S = ut + ½at²
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
S = 4.66*2.35 + ½*5.66*2.35²
S = 10.951 + (2.83 * 5.5225)
S = 10.951 + 15.629
S = 26.58 meters
Answer:
(a) 3.82 x 10⁷ m/s
(b) 4.5 MV/m
Explanation:
(a)
ΔV = change in the electric potential as the proton moves = 7.60 x 10⁶ Volts
q = magnitude of charge on proton = 1.6 x 10⁻¹⁹ C
v = speed gained by the proton
m = mass of proton = 1.67 x 10⁻²⁷ kg
Using conservation of energy
Kinetic energy gained by proton = Electric potential energy
(0.5) m v² = q ΔV
inserting the values
(0.5) (1.67 x 10⁻²⁷) v² = (1.6 x 10⁻¹⁹) (7.60 x 10⁶)
v = 3.82 x 10⁷ m/s
(b)
d = distance over which the potential change = 1.70 m
Electric field is given as
E = ΔV/d
E = 7.60 x 10⁶/1.70
E = 4.5 x 10⁶ V/m
E = 4.5 MV/m
Answer: B
Explanation: The density of a material affects the speed that a wave will be transmitted through it. In general, the denser the transparent material, the more slowly light travels through it. Glass is denser than air, so a light ray passing from air into glass slows down.
To solve this problem we will apply the concept related to kinetic energy based on the ideal gas constant and temperature. From there and with the given values we will find the temperature of the system. As the temperature is the same it will be possible to apply the root mean square speed formula that is dependent on the element's molar mass, the ideal gas constant and the temperature, this would be:
![KE = \frac{3}{2} RT](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20RT)
Where,
KE = Average kinetic energy of an ideal gas
= Ideal gas constant
T = Temperature
Replacing we have,
![KE = \frac{3}{2} RT](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20RT)
![5930J/mol = \frac{3}{2}(8.314JK^{-1}mol^{-1})T](https://tex.z-dn.net/?f=5930J%2Fmol%20%3D%20%5Cfrac%7B3%7D%7B2%7D%288.314JK%5E%7B-1%7Dmol%5E%7B-1%7D%29T)
![T = 475.503K](https://tex.z-dn.net/?f=T%20%3D%20475.503K)
Therefore the temperature is 475.5K
RMS velocity of
gas is
![v_{rms} = \sqrt{\frac{3RT}{M}}](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B3RT%7D%7BM%7D%7D)
Where,
M = Molar mass of ![F_2](https://tex.z-dn.net/?f=F_2)
![M = 38.00g/mol](https://tex.z-dn.net/?f=M%20%3D%2038.00g%2Fmol)
![M = 38.00*10^{-3} kg/mol](https://tex.z-dn.net/?f=M%20%3D%2038.00%2A10%5E%7B-3%7D%20kg%2Fmol)
![T = 475.5K](https://tex.z-dn.net/?f=T%20%3D%20%20475.5K)
![R = 8.314JK^{-1}mol^{-1}](https://tex.z-dn.net/?f=R%20%3D%208.314JK%5E%7B-1%7Dmol%5E%7B-1%7D)
Replacing we have,
![v_{rms} = \sqrt{\frac{3RT}{M}}](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B3RT%7D%7BM%7D%7D)
![v_{rms} = \sqrt{\frac{3(8.314JK^{-1}mol^{-1})(475.5K )}{38.00*10^{-3} kg/mol}}](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B3%288.314JK%5E%7B-1%7Dmol%5E%7B-1%7D%29%28475.5K%20%29%7D%7B38.00%2A10%5E%7B-3%7D%20kg%2Fmol%7D%7D)
![v_{rms} = 558.662m/s](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20558.662m%2Fs)
Therefore, the RMS velocity of
gas is 558.6m/s
It seems reasonable to assume that the car is standing still while the sand is pouring in. Since its speed is zero, it has no momentum, and that won't change until it starts moving, no matter how much sand has been loaded onto it.