<span>Weight is measured as the downward force of gravity.</span>
If one of two interacting charges is doubled, the force between the charges will double.
Explanation:
The force between two charges is given by Coulomb's law

K=constant= 9 x 10⁹ N m²/C²
q1= charge on first particle
q2= charge on second particle
r= distance between the two charges
Now if the first charge is doubled,
we get 
F'= 2 F
Thus the force gets doubled.
At 1.70 atm, a gas sample occupies 4.25 liters. If the pressure in the gas increases to 2.40 atm, what will the new volume be?
Answer:
3.01L
Explanation:
Given parameters:
Initial pressure, P1 = 1.7atm
Initial volume, V1 = 4.25L
Final pressure, P2 = 2.4atm
Unknown:
Final or new volume, V2 = ?
Solution:
To solve this problem, we use Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes, if the temperature is constant".
P1 V1 = P2 V2
P1 is the initial pressure
V1 is the initial volume
P2 final pressure
V2 final volume
1.7 x 4.25 = 2.4 x V2
V2 = 3.01L
Answer:
OPTION A is the correct answer
Answer : The specific heat of aluminum is, 
Solution : Given,
Heat absorbs = 677 J
Mass of the substance = 10 g
Final temperature = 
Initial temperature = 
Formula used :
or,
Q = heat absorbs
m = mass of the substance
c = heat capacity of aluminium
= final temperature
= initial temperature
Now put all the given values in the above formula, we get the specific heat of aluminium.

Therefore, the specific heat of aluminum is, 