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jok3333 [9.3K]
3 years ago
8

State how much energy is transferred in each of the following cases: 2 grams of steam at 100 degrees Celsius condenses to water

at 100 degrees Celsius.
2 grams of boiling water at 100 degrees Celsius cools to ice water at 0 degrees Celsius.
2 grams of ice water at 0 degrees Celsius freezes to ice at 0 degrees Celsius.
2 grams of steam at 100 degrees Celsius turns to ice at 0 degrees Celsius.
Physics
1 answer:
dusya [7]3 years ago
3 0

Answer:

Explanation:

When 2 gms of steam condenses to water at 100 degree latent heat of vaporization is releases which is calculated as follows

Heat released = mass x latent heat of vaporization

= 2 x 2260 = 4520 J

When 2 gms of water  at 100 degree is cooled to ice water at zero degree  heat  is releases which is calculated as follows

Heat released = mass x specific heat x( 100-0)

= 2 x 4.2 x 100 = 840 J

When 2 gms of water at zero degree  condenses to ice at zero degree latent heat of fusion  is releases which is calculated as follows

Heat released = mass x latent heat of fusion

= 2 x 334 = 668 J

When 2 grams of steam at 100 degrees Celsius turns to ice at 0 degrees Celsius heat released will be sum of all the heat released as mentioned above ie

4520 + 840 +668 = 6028 J

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