Answer:
The correct answer would be:
- Genotype ratio: 1 (PP) : 2 (Pp) : 1 (pp)
- Phenotypic ratio: 3 (polka-dot tails) : solid colored tail
The genotype of both parents is Pp (heterozygous).
Thus, both the parent would produce two types of gametes which are P and p.
The cross would result in the production of offspring with three types of genotype PP, Pp, and pp in 1:2:1.
Offspring with PP and Pp will have a polka-dotted tail as it is the dominant trait.
Thus, the phenotype ratio would be 3 (polka-dotted tail) : 1 (solid colored tail).
Answer: Skunk
Explanation: The panda will try to use their slow attack, but the skunk will counter it with their stinky spray that smells bad and the panda will run away.
Answer:
1.31 cM
Explanation:
Total offspring = 2205
Since two genes are involved, F1 progeny should have four types of combination. Out of them two are 17 and 12 which definitely means they are in lesser number. Since recombinants are always less than parental progeny in linkage, the given two types are recombinants.
Recombination frequency = (Number of recombinants / Total progeny) * 100
= [ ( 17 + 12 ) / 2205 ] * 100
= ( 29 / 2205 ) * 100
= 1.31 %
Map distance = Recombination frequency
Hence, distance between two genes = 1.31 cM
Answer:
the type of matter probably turned into a whole different chemical thing
Explanation:
