A particle that is smaller than an atom or a cluster of particles.
Answer
given,
mass of block (m)= 6.4 Kg
spring is stretched to distance, x = 0.28 m
initial velocity = 5.1 m/s
a) computing weight of spring
k x = m g


k = 224 N/m
b) 




c) 


d) 


e)


A = 0.682 m
Force =
=
F = 94.20 N
Complete Question:
An automobile with a mass of 1180 kg is traveling at a speed v =2.51 m/s. What is its kinetic energy in SI units? What speed (m/s) must an 82.7-kg person move to have the same kinetic energy? At what speed (m/s) must is 12.1-g bullet move to have the same kinetic energy? What would be the speed (m/s) of the automobile if its kinetic energy were doubled?
Answer:
a) 3717.1 J b) 9.48 m/s c) 783.8 m/s d) 3.55 m/s
Explanation:
a)
- By definition, the kinetic energy of a mass m with a speed v, is as follows:

- if m= 1180 Kg, and v= 2.51 m/s, the kinetic energy can be calculated as follows:

b)
- If the kinetic energy must be the same, and m= 82,7 Kg, we can write the following expression:

- We can solve the above equation as follows:

c)
- If K remains the same, and m = 12.1 g = 0.0121 kg (in SI units). we can solve for v as follows:

d)
- Now, if the kinetic energy were doubled, we would have the following equation:

- We can solve for the new speed v as follows:
