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Varvara68 [4.7K]
3 years ago
11

For an object that is speeding up at a constant rate in the positive direction,

Physics
1 answer:
Alla [95]3 years ago
7 0

Answer:

B. A line angled upward

Explanation:

velocity is plotted along y- axis and time is plotted along x- axis so we get a line angled upward

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How much heat is needed to melt 1.5kg of ice and then to raise the temperature of the
Kipish [7]

Answer:

> The amount of heat required to melt ice and raise the temperature of water T o C T^oC ToC is Q = m L f + m c Δ T Q=mL_f+mc\Delta T Q=mLf+mcΔT Here m = 1.5 k g m=1.5 kg m=1.5kg L f = 3.33 ∗ 1 0 5 J

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3 years ago
Power can be defined as?
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B. How much work can be done in a given time. That’s why it’s measured occasionally I. “Horsepower.” It’s your ability to work fast and far.
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3 years ago
An object begins with a speed of 20 meters per second and slows down to a speed of 10 meters per second over a time of 5 seconds
Andreyy89

Answer:

V = 6 m/s

Explanation:

Given that,

Initial speed of an object is 20 m/s

Final speed of an object is 10 m/s

Time, t = 5 s

We need to find the average speed of the object during these 5 seconds. Let it is equal to V. Here, time is same. The average speed is given by :

V=\dfrac{x+y}{2}\\\\\text{Putting values}\\\\V=\dfrac{20+10}{5}\\\\V=6\ m/s

So, the average speed of the object is 6 m/s.

3 0
3 years ago
As an object accelerates to a speed close to the speed of light, which of the following stays the same?
kirill115 [55]
A. Speed of light (Apex) 
6 0
3 years ago
Read 2 more answers
Refer to the attached image!!!​
dimaraw [331]

The time of motion of the track star is determined as 0.837 s.

<h3>Time of motion of the track star</h3>

The time of motion of the track star is calculated as follows;

T = (2u sinθ)/g

where;

  • T is time of motion
  • g is acceleration due to gravity
  • θ is angle of projection

T = (2 x 12 x sin20)/9.8

T = 0.837 s

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

6 0
2 years ago
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