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Dennis_Churaev [7]
3 years ago
9

Explain the advantages of using parallel circuits to series circuits in wiring rooms

Physics
1 answer:
irina [24]3 years ago
5 0

The major advantage of parallel circuit which makes it advantageous in the application of wiring rooms are the supply of equal voltage across each circuit, which is not present in series circuit.

<u> Explanation:</u>

The use of parallel circuit is preferred over series circuit while wiring the room as the parallel gives the same voltage across every circuit which keeps it safe from damaging or burning as they give consistent voltage.

Apart from this, the parallel circuit allows you for independent operation without letting use of all the equipment present in the room. Then there is scope for additional components without changing the voltage.

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A large blue marble of mass 3.5 g is moving to the right with a velocity of 15 cm/s. The large marble hits a small red marble of
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Explanation:

Let's solve the problem by using conservation of momentum:

m1 u1 + m2 u2 = m1 v1 + m2 v2

where:

m1 = 3.5 g  is the mass of the blue marble

m2= 1.2 g is the mass of the red marble

u1 = 15 cm/s  is the initial velocity of the blue marble

u2 = 3.5 cm/s is the initial velocity of the red marble

v1 = 5.5 cm/s is the final velocity of the blue marble

We can find the final velocity of the red marble by re-arranging the equation and solving for v2 :

v2 = 1/m²(m1 u1 + m2 u2 - m1 v1)=

=1/1.2(3.5×15+1.2×3.5−3.5×5.5 )=31cm/s

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Bowling Ball

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Read 2 more answers
The voltage V in a circuit that satisfies the law V = IR is slowly dropping as the battery wears out. At the same time, the resi
Anastasy [175]

Answer:

-0.5\times 10^{-4} A/s

Explanation:

We are given that

\frac{dV}{dt}=-0.01 V/s

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V=IR

\frac{dV}{dt}=\frac{\partial V}{dI}\frac{dI}{dt}+\frac{\partial V}{dR}\frac{dR}{dt}

\frac{dV}{dt}=R\frac{dI}{dt}+I\frac{dR}{dt}

Substitute the values

-0.01=600\times \frac{dI}{dt}+0.04\times 0.5

-0.01-0.04\times 0.5=600\frac{dI}{dt}

-0.03=600\frac{dI}{dt}

\frac{dI}{dt}=\frac{-0.03}{600}=-0.5\times 10^{-4}A/s

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4 years ago
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