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Cerrena [4.2K]
3 years ago
13

What's equivalent to 2x+3x+8-3x-2? Options arte 2x+6, 2x+10, 5x-3x+6, 5x-3x+10 Select all that are equivalent.

Mathematics
2 answers:
victus00 [196]3 years ago
8 0
2x+6 I believe is the answer
jeka943 years ago
4 0

Answer:

2x+6, 5x-3x+6

Step-by-step explanation:

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What is the domain and range of this function?
max2010maxim [7]

As for the domain, the only restriction comes from the logarithm. The argument of a logarith must be strictly positive, so we have

x-2>0 \iff x>2

As for the range, we have:

  • The range of \log(x) are all real numbers
  • If we change to \log(x-2) we're translating the function horizontally, so the range remains the same
  • If we change to \log(5(x-2() we're stretching the function horizontally, so the range doesn't change
  • If we change to \log(5(x-2))+1 we're translating the function 1 unit up, but the range is already all the real numbers, so it doesn't change.

5 0
3 years ago
An object is moving at a speed of 2 feet every 8.5 minutes. Express this speed in meters per hour
jekas [21]

Answer:

4.30m/hr

Step-by-step explanation:

2 feet/8.5 mins is 0.235294118 feet per minute, which is 4.3030553875397 metres per hour, which to 2 s.f. is 4.30

8 0
3 years ago
What is the sum of all the positive integers from <br> √<br> 24<br> to <br> √<br> 102<br> ?
Eva8 [605]

Answer:

The sum of all positive integers is

5 + 6 + 7 + 8 + 9 + 10

              = <em>45</em>

Step-by-step explanation:

Because \sqrt{24} = 4.89 and \sqrt{102} = 10.09

So positive numbers between 4.9 and 10.09 are

 <em>5+6+7+8+9+10 = 45</em>

<em />

<em>Brainliest will be appreciated.</em>

7 0
3 years ago
In AGHI, the measure of G=76º, and IG = 6.2 feet. Find the length of HI to the nearest tenth of a foot.
Whitepunk [10]
Wow that’s so cooler than the last
4 0
3 years ago
Given: AE ≅ CE ; DE ≅ BE Prove: ABCD is a parallelogram. Parallelogram A B C D is shown. Diagonals are drawn from point A to poi
nikklg [1K]

Answer:

The proof is below

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC              (∵Opposite sides of a parallelogram are equal)

∠DAC=∠BCE       (∵Alternate angles)

∠ADC=∠CBE        (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE

6 0
3 years ago
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