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pentagon [3]
3 years ago
13

HELP PLEASE ITS DUE!!!! PLEASE I NEED HELPPPPPPP

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
Hey, so basically just plug in the x values for x in the equation. First table the first x value is -1 so just plug it in to 3x so: 3(-1)= -3. That’s your y.
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3 years ago
Which equation represents a circle that contains the point (-5, -3) and has a center at (-2, 1)?
Evgen [1.6K]

The equation (x + 2)² + (y - 1)² = 25 represents a circle that contain the point (-5 , -3) and has a center at (-2 , 1)

Step-by-step explanation:

The equation of a circle of center (h , k) and radius r is:

(x - h)² + (y - k)² = r²

The given is:

  • The center of the circle is (-2 , 1)
  • The circle passes through point (-5 , -3)

The length of the radius is the distance from the center of the circle

to a point on the circle

∵ The formula of the distance is d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∵ The center of the circle is (-2 , 1)

∵ The circle passes through point (-5 , -3)

∴ r=\sqrt{[(-5)-(-2)]^{2}+[(-3)-(1)]^{2}}

∴ r=\sqrt{[-3]^{2}+[-4]^{2}}

∴ r=\sqrt{9+16}

∴ r=\sqrt{25}

∴ r = 5

∵ The equation of the circle is (x - h)² + (y - k)² = r²

∵ The center of the circle is (-2 , 1)

∴ h = -2 and k = 1

∵ r = 5

∴ r² = (5)² = 25

- Substitute the values of h , k , r² in the equation of the circle

∴ (x - -2)² + (y - 1)² = 25

∴ (x + 2)² + (y - 1)² = 25

The equation (x + 2)² + (y - 1)² = 25 represents a circle that contains

the point (-5 , -3) and has a center at (-2 , 1)

Learn more:

You can learn more about the equation of the circle in brainly.com/question/9510228

LearnwithBrainly

7 0
3 years ago
How do you solve this problem? (x+3) cubed
Lubov Fominskaja [6]
You would expand becausee it isn't equal to anything

(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one

so
for the 3rd power
(a+b)^3=1a^3+3a^2b^1+3a^1b^2+1b^3

a=x
b=3

(x+3)^3=1x^3+3x^2(3^1)+3x^1(3)^2+1(3)^3=
x^3+9x^2+27x+27


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