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lorasvet [3.4K]
3 years ago
13

I Need help

Mathematics
1 answer:
Ivan3 years ago
3 0

Answer:

1.) Verbal Expression: m is less than 4

2.) 4th or s ≤ 30

3.) Verbal Expression: q is not equal to 3

Hope this helps!

You might be interested in
find the area and perimeter using the lengthy and with step by step I will give 40 points please answer right number 6,7,9,10,11
N76 [4]

Answer:

6. 16 meters^2, 16 meters

7. 100 milimieters^2, 40 milimeters

9. 56 centimeters^2, 30 centimeters

10. 49 inches^2, 28 inches

11. 9 meters^2, 12 meters

12. 72 yards^2, 36 yards

Step-by-step explanation:

s is for a square

A=s^2

P=4s

l+w is for a rectangle

A=lw

P=2l+2w

6. A=4^2

A= 16 meters^2

P=4*4

P= 16 meters

7. A=10^2

A=100 milimieters^2

P=4*10

P= 40 milimeters

9. A=8*7

A= 56 centimeters^2

P=2(8)+2(7)

P=30 centimeters

10. A=7^2

A=49 inches^2

P=4*7

P=28 inches

11. A= 3^2

A=9 meters^2

P=4*3

P= 12 meters

12.

A=12*6

A=72 yards^2

P= 2(12)+2(6)

P= 36 yards

Let me know if you have any questions. Also, don't forget units!

4 0
2 years ago
Can Someone Answer My Final Answers :) I’d appreciate it so much :)
DaniilM [7]
1. Remember that the perimeter is the sum of the lengths of the sides of a figure.To solve this, we are going to use the distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
(x_{1},y_{1}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point
Length of  WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}
d_{WZ}= \sqrt{(3)^2+(2)^2}
d_{WZ}= \sqrt{9+4}
d_{WZ}= \sqrt{13}

We know that all the sides of a rhombus have the same length, so 
d_{YZ}=  \sqrt{13}
d_{XY}= \sqrt{13}
d_{XW}= \sqrt{13}

Now, we just need to add the four sides to get the perimeter of our rhombus:
perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}
perimeter=4 \sqrt{13}
We can conclude that the perimeter of our rhombus is 4 \sqrt{13} square units. 

2. To solve this, we are going to use the arc length formula: s=r \alpha
where
s is the length of the arc. 
r is the radius of the circle.
\alpha is the central angle in radians

We know form our problem that the length of arc PQ is \frac{8}{3}  \pi inches, so s=\frac{8}{3} \pi, and we can infer from our picture that r=15. Lest replace the values in our formula to find the central angle POQ:
s=r \alpha
\frac{8}{3} \pi=15 \alpha
\alpha =  \frac{\frac{8}{3} \pi}{15}
\alpha = \frac{8}{45} \pi

Since \alpha =POQ, We can conclude that the measure of the central angle POQ is \frac{8}{45} \pi

3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut  in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section. 
We can conclude that the draw of our cross section is:

6 0
3 years ago
Read 2 more answers
How much interest did you gain if you invested in a retirement plan with a rate of 2.5% over 42 years? Your monthly deposits tot
andreyandreev [35.5K]

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

7 0
3 years ago
Will give brainliest
kodGreya [7K]

Answer: y=12 x =9

Step-by-step explanation:

In a parallelogram the diagonals bisect each other making them equal.

this means 2y + 6 = 30

we can rearrange this as 30 - 6 = 2y

24 = 2y  therefore y = 12

3x - 3 = 24

We can rearrange this as 24 + 3 = 3x

3x = 27

27 / 3 = 9

x = 9

Hope this helped :)

3 0
3 years ago
PLEASE HELP! I HAVE A TIME CRUNCH! WILL MARK BRAINLIEST!! LOVE Y'ALL Fill in each * so that the statement is true.
siniylev [52]

Answer:

a, (x^2)^3 = x^6 = x^2.x^4

b, x^5·x^7 = x^12 = (x^3)^4

c, x^4·x^22 = x^26 = (x^2)^13

d, (x^2)^8 = x^16 = x^2.x^14

e, x^10/x^3 = x^7 = x^20.x^(-13)

f, x^(-3) = x^4.x^(-7)

g, 1/x^(-3) = x^3 = x^4.x^(-1)

Hope this helps!

:)

6 0
3 years ago
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