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3 years ago

I Need help

Mathematics

1 answer:

Ivan3 years ago

3 0

Answer:

1.) Verbal Expression: m is less than 4

2.) 4th or s ≤ 30

3.) Verbal Expression: q is not equal to 3

Hope this helps!

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Write the ratios for Sin A Cos A, and Tan A.

Nataliya [291]

Step-by-step explanation:

sinA= BC/AC

= 24/26

= 12/13

cosA= AC/AB

= 10/26

= 5/13

tanA= BC/AC

=24/10

= 12/5

4 0

3 years ago

Read 2 more answers

If x = y then 3x = 3y gemotry prove

otez555 [7]

Multiplying both sides of an equation by the same number keeps the equation true. In this example, both sides are multiplied by 3, so the equation isn't changed.

6 0

3 years ago

Carl deposited $5,142 into a savings account 20 years ago. The account has an interest rate of 3.8% and the balance is currently

Aleksandr [31]

Here is the formula you'll need
Total = Principal * (1 + (rate/n))^n*years
I don't know how to solve that for "n" so we'll use trial and error.

If compounded annually, total = 10,841.24 
If compounded quarterly, total = 10,955.64 
If compounded monthly, total = 10,981.82 
If compounded daily, total = 10,994.58 
Therefore the answer is "A", daily.

Source:
http://www.1728.org/compint3.htm

3 0

4 years ago

Write and solve inequality ;10 more than 6 times a number is greater than 46

meriva

Is 16x47 what you're asking for? The answer to 16x47 is 752 if that's what you needed.

5 0

4 years ago

Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective

soldier1979 [14.2K]

Answer:

a) $P[C]=p^n$

b) $P[M]=p^{8n}(9-8p^n)$

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

$P[C]=p^n$

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

$P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)$

$P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9$

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

$P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2$

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0

4 years ago