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vazorg [7]
3 years ago
10

Lorena is trying to choose between two different savings accounts at H-Town Bank. She will deposit $3,500 dollars and will leave

the money in the account for 12 years. There will be no additional money deposited or withdrawn from the account. Advanced Savings Account. Initial Deposit three thousand five hundred. Account earns 5 percent simple interest. Premier Savings account. Initial Deposit three thousand five hundred. Account earns four point five percent interest compounded annually. Which statement about the accounts will be true at the end of 12 years?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0

Answer:

GET REKTTKTKTTK

Step-by-step explanation:

SJDHDIAJSJSJSJAJ

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Which of the following groups of numbers are integers?
Alenkasestr [34]
A and C are the correct answers
4 0
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The directions are write and solve two step equations
Aneli [31]

Answer:

Sarah is 22

Step-by-step explanation:

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3 0
3 years ago
If one angle of a set of supplementary angles measures 77°, then the other angle measures _____.
juin [17]

Answer:

B

Step-by-step explanation:

Supplementary angles sum to 180°

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3 0
3 years ago
Solve the equation below. Indicate which solutions, if any, are extraneous.<br> √ x+5 = x+3
ahrayia [7]

9514 1404 393

Answer:

  x = -1

Step-by-step explanation:

A graphical solution can avoid extraneous solutions. The attachment shows the one solution is x = -1.

__

Squaring both sides gives ...

  x +5 = (x +3)² = x² +6x +9

Putting this in standard form, we have ...

  x² +5x +4 = 0

  (x +1)(x +4) = 0 . . . . . factor

  x = -1 or -4 . . . . . . . . values of x that make the factors zero

__

Since we require the root to be non-negative, we must have ...

  x +3 ≥ 0

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The only solution that satisfies this requirement is x = -1. The solution x = -4 is extraneous. The solution is x = -1.

3 0
3 years ago
Given: ΔPSQ, PS = SQ PΔPSQ = 50 SQ – PQ = 1 Find: Area of ΔPSQ
Pachacha [2.7K]
The first part is to find the length SQ which is equal to SP.
Use the sine rule.
SQ/sin 65 = (SQ - 1)/Sin50
(sin50)/(sin 65) = (SQ-1)/SQ
0.8452(SQ) = SQ-1
0.1547SQ = 1
SQ = 6.46 
The formula to apply here is:
Area=1/2(SQ)(SQ)sin50
        = 0.5 × 6.46 × 6.46 × sin50
        = 15.984
3 0
3 years ago
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