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attashe74 [19]
2 years ago
5

Is it possible to have kinetic energy and potential energy? What about neither? Give an example of each!

Physics
1 answer:
Serhud [2]2 years ago
5 0
Yes they are both possible. An example of having both kinetic and gravitational potential energy could possibly be when you are travelling on a roller coaster. You are in motion and at a height. An example of neither could just be an individual sitting on a floor. They are neither in motion or at a height. Hope that helps :)
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3 years ago
A 18.0-kg rock is sliding on a rough, horizontal surface at 7.10 m/s and eventually stops due to friction. the coefficient of ki
Bond [772]
A = .3*g = 2.94 m/s² 

<span>t = v/a = 9/2.94 = 3.061 sec </span>

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3 years ago
A ball moving at positive 3.0 m per s along a table rolls off a table and lands on the ground 2.0 m away. How high was the table
MA_775_DIABLO [31]

consider the motion along the horizontal direction :

v₀ = initial velocity in horizontal direction as the ball rolls off the table = 3.0 m/s

X = horizontal displacement of the ball = 2.0 m

a = acceleration along the horizontal direction = 0 m/s²

t = time taken to land = ?

using the kinematics equation

X = v₀ t + (0.5) a t²

2.0 = 3.0 t + (0.5) (0) t²

t = 2/3


consider the motion of the ball along the vertical direction

v₀ = initial velocity in vertical direction as the ball rolls off the table = 0 m/s

Y = vertical displacement of the ball = height of the table = h

a = acceleration along the vertical direction = 9.8 m/s²

t = time taken to land = 2/3

using the kinematics equation

Y = v₀ t + (0.5) a t²

h = 0 t + (0.5) (9.8) (2/3)²

h = 2.2 m


C 2.2 m

3 0
3 years ago
If you shake one end of a rope up and down , a wave passes through the rope. Which type of wave is it?
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Answer: a transverse wave

Explanation:

8 0
2 years ago
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A car is traveling at a speed of 10m/s. A 0.5kg clump of mudis
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Answer:B

Explanation:

Given

speed of car v=10 m/s

mass of clump m=0.5 kg

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Since the tire is rotating about axle so a centripetal force is acting constantly on each particle towards the center of tire.

Centripetal force is given by

F_c=\frac{mv^2}{r}

where m=mass\ of\ element

v=speed

r=distance\ from\ center

F_c=\frac{0.5\times 10^2}{0.2}

F_c=250\ N (inward)

           

3 0
3 years ago
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