A shuffleboard disk is accelerated to a speed of 5.8 m/s and released. If the coefficient of kinetic friction between the disk a
nd the concrete court is 0.31, how far does the disk go before it comes to a stop?
1 answer:
Answer:
5.53 m
Explanation:
= initial speed of shuffleboard disk =
= final speed of shuffleboard disk =
= Coefficient of kinetic friction between the disk and concrete court = 0.31
acceleration due to friction is given as

= distance traveled by disk before it stops
using the kinematics equation that fits the above the data, we have

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