A 18.0-kg rock is sliding on a rough, horizontal surface at 7.10 m/s and eventually stops due to friction. the coefficient of ki
netic friction between the rock and the surface is 0.175. what average power is produced by friction as the rock stops?
1 answer:
A = .3*g = 2.94 m/s²
<span>t = v/a = 9/2.94 = 3.061 sec </span>
<span>W = E/t = ½mv²/t = ½*40*9²/3.061 = 529.2 watts</span>
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Answer:someone help me
Explanation:
KE = 1/2 x 80 x 60^2
KE = 144000
