What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2
x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic
x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3
5x - 3 = 0
No it is not a quadratic because it does not have x^2
2x^2 + 12x = 0
Yes because there's x^2
5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2
9x^2 + 6x - 3 = 0
Yes because there's x^2
Could you tell me what the question is?
Answer:
no solution exists:
Step-by-step explanation:
x²−1x+10=0
Step 1: Simplify both sides of the equation.
x²−x+10=0
Step 2: Subtract 10 from both sides.
x²−x+10−10=0−10
x²−x=−10
Step 3: The coefficient of -x is -1. Let b=-1.
Then we need to add (b/2)^2=1/4 to both sides to complete the square.
Add 1/4 to both sides.
x²−x+
1/4=−10+
1/4
x²−x+
1/4=−39
/4
Step 4: Factor left side.
(x -1/2)² = −39
/4
Step 5: Take square root.
x −1
/2 =±√
−39
/4
Step 6: Add 1/2 to both sides.
x =−1/2 + 1/2 = 1/2 ±√
-39/4
x = 1/2 ±√
-39/4
No real solutions.
Answer:
Step-by-step explanation:
Hello!
10*17 = > 170 cm²
(3,14 * 8)/4 =>6,28cm²
170 + 6,28 => 176,28cm²
Answer:1437
Step-by-step explanation:
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