Answer: The compound is nickel (II) chloride.
NiCl2
Explanation:
Let's assume that the compound is X.
Then,
XCl2 + 2AgNO3 ---> X(NO3)2 + 2AgCl
Given,
Volume of AgNO3 = 22.4ml = 0.0224L
Concentration of AgNO3 = 0.515M
no of moles = concentration x volume
:• n(AgNO3) = 0.515 x 0.0224
n(AgNO3) = 0.011536 mol
Therefore, no of moles of AgNO3 is 0.0011536mol
From the equation above, we can deduce that;
n(XCl2) = 1/2n(AgNO3)
:• n(XCl2) = 1/2 × 0.011536
n(XCl2) = 0.005768
Therefore number of moles of XCl2 is 0.005768 mol.
Mass, m, of XCl2 = 0.75g (Given)
Molar mass = mass/ no of moles
Molar mass of XCl2 = 0.75/0.005768
:• molar mass of XCl2= 130.03g/mol
Molar mass of Cl = 35.453
Cl2= 2 x 35.453 = 70.906
Molar mass of XCl2 = M.mass of X +
M.mass of Cl2
:• 130.03 = M.mass of X + 70.906
Molar mass of X = 130.03 - 70.906
Molar mass of X = 59.1
By comparing to literature, we can conclude that X is Nickle ,Ni.
Therefore, the compound is NiCl2 , Nickle(II) Chloride.
