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Elden [556K]
3 years ago
11

A bowler lifts her bowling ball a distance of 0.5 meters using 35 joules of energy. If, on Earth, a 1.0 kilogram mass weighs 9.8

newtons, the mass of the bowling ball used by this bowler is about;
Chemistry
1 answer:
kherson [118]3 years ago
8 0

Answer:17.5

Explanation: (0.5 meters)(35 Joules) =

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How many liters of a 6.0M solution Fe(SCN)2 are needed to prepare 2.0L of a 0.75M solution?
lubasha [3.4K]

Answer:

0.25L

Explanation:

Using the dilution formula

C1V1=C2V2

C1=6M

V1?

C2=0.75M

V2=2.0L

V1= C2V2/C1

V1=0.75*2.0/6

V1=0.25L

4 0
3 years ago
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12. A voltaic cell consists of a chromium electrode dipped in a 1.20 M chromium (III) nitrate
Lilit [14]

For a voltaic cell consisting of chromium, an electrode dipped in a 1.20 M chromium (III) nitrate solution and a tin electrode dipped in a 0.400 M tin (II) nitrate solution, the cell potential at 298 K  is mathematically given as

Ecell = 0.577 V

<h3 /><h3>What is the cell potential at 298 K?</h3>

Generally, the equation for the Oxidation and Reduction  is mathematically given as

Cr(s) ------------------ Cr+3(aq) + 3e- ] x 2 ...O

Sn+2(aq) + 2e- ------------ Sn(s) ] x 3  ...R

Reaction

 2 Cr(s) + 3 Sn+2(aq) --------------- 2 Cr+3(aq) + 3 Sn(s)

Therefore

Eicell = - 0.14 - ( - 0.74)

Eicell = 0.60

In conclusion

Ecell= E0cell - \frac{0.0591}{n} * \frac{log[Cr+3]^2}{ [ Sn+2]^3}

Ecell = 0.60 - \frac{0.0591 }{6} \frac{log( 1.20)^2}{ ( 0.200)^3}

Ecell = 0.577 V

Read more about Temperature

brainly.com/question/13439286

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2 years ago
Where would you find almost no wind at all?
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Answer:

A. the prevailing westerlies

7 0
3 years ago
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How do solve for #13?What is the boiling point of a solution made by dissolving 1.0000 mole of sucrose in 1.0000 kg of water?
exis [7]

What is the boiling point of a solution made by dissolving 1.0000 mole of sucrose in 1.0000 kg of water?

The change in Boiling Point of water can be calculated using this formula:

ΔTb = i * Kb * m

Where i is the van't hoff factor (the number of particles or ions), the kb is a constant (boiling point elevation constant) and m is the molality of the solution.

The kb for water is always 0.515 °C/m. Kb = 0.515 °C/m

The value for i in this case is 1. Since sucrose is a covalent compound and it doesn't dissociate into ions. i = 1

The molal concentration of the solution can be found using this formula:

molality = moles of sucrose/kg of water

molality = 1.000 mol / 1.000 kg of water

molality = 1 m

Now that we know all the values, we can use the formula to find the change in the boiling point of water:

ΔTb = i * Kb * m

ΔTb = 1 * 0.515 °C/m * 1 m

ΔTb = 0.515 °C

Finally, we are asked for the boiling point of the solution, not the change. The boiling point of water at atmospheric pressure is 100.00 °C. If the boiling point rises 0.515 °C when we prepare the solution. The boiling point of the solution is:

Boiling point solution = Boiling point of water + ΔTb

Boiling point solution = 100.000 °C + 0.515 °C

Boiling point solution = 100.515 °C

Answer: The boiling point of the solution is 100.515 °C.

8 0
1 year ago
The image shows the street lights powered by its solar panels.which sequence shows the energy transformations taking place in th
mars1129 [50]

Answer:

theres no pic

Explanation:

7 0
3 years ago
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