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vladimir2022 [97]
3 years ago
14

Please Help Me Will Pick the first correct answer brainliest

Mathematics
1 answer:
dimaraw [331]3 years ago
8 0

Answer:

1 and 4 are correct :)

Step-by-step explanation:

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What is an estimate of 23 times 67
Ber [7]
What is an estimate of 23 times 67
1,500
8 0
3 years ago
Evaluate lim x=π/4(3x - tanx)​
Karo-lina-s [1.5K]

Answer:

 \lim_{x \to\frac{\pi }{4} } (3x-tanx) =  3(\frac{\pi }{4}  )

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that

         \lim_{x \to\frac{\pi }{4} } (3x-tanx)

  =  \lim_{x \to\frac{\pi }{4} } (3x) -  \lim_{x \to\frac{\pi }{4} }  tanx)

 = 3(\frac{\pi }{4} )+tan(\frac{\pi }{4} )

=  3(\frac{\pi }{4} )+ 1 )

=  3(\frac{\pi }{4}  )

5 0
3 years ago
The volume of this cylinder is 20,403.72 cubic yards. What is the radius? Use ​ ≈ 3.14 and round your answer to the nearest hund
MakcuM [25]
The formula for the volume of a cylinder is V=3.14r^2(h).
So substituting the volume: 20,403.72=3.14r^2(h).

To solve for ‘r’, divide both sides by 3.14h
r^2=6,498/h
Then find square root of both sides
r= sqrt(6,498/h)
Since ‘h’ is not specified here, it cannot be solved further.
4 0
2 years ago
I need help with these 2 problems I cant figure out.
Alla [95]

I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.

2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)

Next, I add 20 on both sides.

2x + 90 + 3x = 200º

I combine like terms (2x and 3x)

5x + 90 = 200º

I subtract 90 from both sides.

5x = 110º

Divide 110 by 5 to get x.

x = 22

======

For problem two, I label all the angles I know.

49º + 80º + r = 180º

I add 80 and 49.

129º + r = 180º

I subtract 180 and 129 and get 51º, which is your angle for R.

For angle X, you know that angle R plus angle X equals half of a circle, which is 180º

We know from before that 129º is 180º without R, so X is 129º

I hope this helps! Let me know if I'm wrong!

5 0
3 years ago
Answer this ASAP please​
larisa86 [58]

Answer:

V = 339.12 yd^{3}

7 0
3 years ago
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