It's 3/2. wat else u need?
assuming mean=0 and sd = 1; you want to find the z-score that corresponds to the first 20% of the graph.
The z-score is found in my "z-table" by subtracting 20% from 50% to obtain the distance away from the mean value.
When I look at the z-table in the back of the book, I want to find a number in the middle of the table that is closest to ".3000" (50% - 20% = 30%)
The closest value I find in the field is: .2995. I follow this out to the left (.8) and up to the top (.04) to get the numbers for the z-score: left+top. z-score = .84
This has to be evaluated for its placement. If the z-score is to the left of the mean; we negate it; if its to the right of the mean, we keep it a positive value.
20% is less than 50% so its to the left of our mean: z-score = -.84
............................................9
Answer:
X/360 (r^2)
Step-by-step explanation:
If X is the number of degrees of the sector, then the area will be given by
X/360 *r^2
Where r^2 is the radius of the circle. The denominator of X is 360 because the degrees of a circle add up to 360
For instance, if the sector is half the circle, then we have
180/360 *r^2 (or 0.5(360)*r^2)
Answer: 6 1/10
Step-by-step explanation: