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Tanya [424]
3 years ago
7

I WILL NAME YOU BRAINLIEST AND GIVE YOU ALL MY POINTS IF YOU SOLVE THIS!!!!! In the diagram, each shape has a value and the sums

of the shapes in each of the first three rows is given. Find the sum of the shapes in the fourth row.
Mathematics
2 answers:
DedPeter [7]3 years ago
8 0

Answer:

Can you put up the diagram so I can solve it?

Step-by-step explanation:

cluponka [151]3 years ago
7 0

Answer:

...

Step-by-step explanation:

...

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Grant made a $2800 investment that piece is simple interest rate at 6% per year. To the nearest hundredth which of the following
VARVARA [1.3K]
F i just did that question on a test a while ago
6 0
3 years ago
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Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
When measuring weight 6 small dogs are approximately equal to 9 large cats.
Zolol [24]

Answer:

See below

Step-by-step explanation:

Equation 1:

Step 1:

6 : 9 = x : 54      Ratio

Step 2:

9x = 324     Multiply

Step 3:

36 small dogs       Divide

Equation 2:

Step 1:

6 : 9 = x : 12       Ratio

Step 2:

9x = 72     Multiply

Step 3:

8 small dogs   Divide

First Answer:

36 small dogs

Second Answer:

8 small dogs

Hope This Helps :)

7 0
3 years ago
Expand (x^2-3/2)^9 using binomial process
BaLLatris [955]
Use the Binomial expansion theorem to find and simplify each term.

x^{18} - \frac{ 27x^{6} }{2}+ 81x^{14}- \frac{ 567x^{12} }{2}+ \frac{ 5103x^{10} }{16}- \frac{ 15309x^{8} }{16}+ \frac{ 15309x^{6} }{16} - \frac{ 59049x^{2} }{256}-\frac{19683}{512}

Man that was a lot to type out, hopefully i helped, and Gosh I hope I get a brainly for all that freaking typing. hehe~ ^.^
8 0
3 years ago
Determine whether AB is a median,altitude,or neither
nasty-shy [4]

Answer:

median

Step by step:

the line segment from a vertex to the midpoint of the opposite side. It is also an angle bisector when the vertex is an angle in an equilateral triangle or the non-congruent angle of an isoceles triangle.

7 0
2 years ago
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