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ohaa [14]
3 years ago
5

 please HURRY I WILL GIVE BRAINLEST Which expression is equivalent to -6 (3X-2/3)

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer: -18x + 4

Step-by-step explanation:

-6 (3x - 2/3)

= (-6) (3x + -2/3)

= (-6) (3x) + (-6) (-2/3)

= -18x + 4

Kisachek [45]3 years ago
6 0

Answer:

The answer is (-18x+4)

Step-by-step explanation:

We do the rainbow method were we multiply whats outside the parenthesis to whats inside the parenthesis.

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Fill in the missing numbers below.
Levart [38]

Answer:

5 feet + 12 inches = 2 yards

48 inches = 1 foot + 1 yard

5 feet = 3 feet + 24 inches

Step-by-step explanation:

To help solve these equations, you must know how to convert feet to inches, inches to yards, etc. Use the information below:

1 feet = 12 inches

3 feet = 1 yard

To solve 5 feet + 12 inches = blank yard(s), convert 5 feet & 12 inches to yards. Since 5 feet would be complicated to convert, let's convert 12 inches to feet first.

12 inches = 1 feet

Instead of 12 inches, we can substitute it as 5 feet + 1 feet = blank yard(s). That would be 6 feet = ? yards. 3 feet = 1 yard, which tells us we must divide both sides by 3. Thus, 5 feet + 12 inches = 2 yards.

Blank inches = 1 foot + 1 yard

To find the # of inches in a yard, you must first know that 3 feet = 1 yard. If there are 12 inches in a foot, we must multiply 3 by 12, getting us 36. You add 12 inches (1 foot), getting us 48 inches in total. Thus 48 inches = 1 foot + 1 yard.

Blank feet = 3 feet + 24 inches

Since 3 feet is already feet, we do not need to convert it. If 12 inches is 1 foot, we must divide 24 inches by 12. So, there is 2 feet in 24 inches. 2 + 3 is 5. Thus, 5 feet = 3 feet +24 inches.

8 0
3 years ago
Does anyone know how to do this help please
statuscvo [17]

Answer:

\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

\rm\implies y = x^2+x - 6

Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 3^2-3-6\\

\rm\implies y = 9 - 3 - 6 \\

\rm\implies y = 0

<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 2^2-2-6\\

\rm\implies y = 4 -2-6\\

\rm\implies y = -4

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = -1^2-1-6\\

\rm\implies y = 1 -1-6 \\

\rm\implies y = -6

<u>Put </u><u>x </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 1^2+1-6\\

\rm\implies y = 2 -6

\rm\implies y = -4

<u>Put </u><u>x </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 2^2+2-6\\

\rm\implies y = 4 +2-6\\

\rm\implies y = 2

<u>Put </u><u>x </u><u>=</u><u> </u><u>3 </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 3^2+3-6\\

\rm\implies y = 9 +3-6\\

\rm\implies y = 6

<u>Final </u><u>table</u><u> </u><u>:</u><u>-</u><u> </u>

\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

7 0
3 years ago
How many 4 minutes and 30 seconds in 2 hours
AleksAgata [21]

4 minutes and 30 seconds go into 2 hours 26 times

119

7 0
4 years ago
Read 2 more answers
What is the measure of angle 15
Mademuasel [1]

Answer:

A

Step-by-step explanation:

m<15 = m<1 because of how the transversals are placed. so m<1 = 90º - 65º = 25º

that means that m<15=25º

7 0
3 years ago
Read 2 more answers
How do i solve for x
Dafna11 [192]

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! so im pretty sure its 20

5 0
3 years ago
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