Interpreting the graph and the situation, it is found that the values of d that can be included in the solution set are 1 and 4.
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- According to Benford's law, the probability of a number starting with digit is d is:

- A number can start with 10 possible digits, ranging from 1 to 9, which are all integer digits.
- Thus, d can only assume integer digits.
- In the graph, the solution is d < 5.
- The integer options for values of d are 1 and 4.
- For the other options that are less than 5, they are not integers, so d cannot assume those values.
A similar problem is given at brainly.com/question/16764162
Here, AB ║ CD ; EF ⊥ AB
Number of 90 degree formed by the intersections of EF and two parallel lines AB and CD is 8
Hope this helps!
I believe the answer is A. 20, 30, 40 is NOT a pythagorean triple.
Answer:
I graphed both equations to find the solutions.
Step-by-step explanation:
When x is 0, y is -6. When x is 7, y is 8.
x = 0 and 7
3 times 7= 21 times three =63