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ohaa [14]
3 years ago
5

 please HURRY I WILL GIVE BRAINLEST Which expression is equivalent to -6 (3X-2/3)

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer: -18x + 4

Step-by-step explanation:

-6 (3x - 2/3)

= (-6) (3x + -2/3)

= (-6) (3x) + (-6) (-2/3)

= -18x + 4

Kisachek [45]3 years ago
6 0

Answer:

The answer is (-18x+4)

Step-by-step explanation:

We do the rainbow method were we multiply whats outside the parenthesis to whats inside the parenthesis.

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Here’s Question three
Hitman42 [59]

Answer:

BD = 3 units

Step-by-step explanation:

Since, AD is an angle bisector of ∠BAC,

m∠BAD = m∠CAD = 20°

CD = 3 units

In ΔACD and ΔABD,

m∠BAD = m∠CAD = 20° (Given)

AD ≅ AD [Reflexive property]

Therefore, by H-A property of congruence both the triangles will be congruent.

And by CPCTC,

CD ≅ BD = 3 units

5 0
3 years ago
Square root of y^2 times y^2
Galina-37 [17]
<span>Square root of y^2 = y
so
</span><span>Square root of y^2 times y^2 = y * y^2 = y^3

answer
y^3</span>
8 0
3 years ago
A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.
TEA [102]

Answer:

(a) Null Hypothesis, H_0 : \mu = $1,150  

    Alternate Hypothesis, H_A : \mu \neq $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

<u><em>Let </em></u>\mu<u><em> = mean of all account balances</em></u>

(a)So, Null Hypothesis, H_0 : \mu = $1,150     {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, H_A : \mu \neq $1,150    {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                               T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average balance = $1,200

             s = sample standard deviation = $126

             n = sample of account balances = 81

(b) So, <u>test statistics</u>  =  \frac{1,200-1,150}{\frac{126}{\sqrt{81} } }  ~ t_8_0

                               =  3.571

The value of the sample test statistics is 3.571.

(c) <u>Now, P-value of the test statistics is given by the following formula;</u>

          P-value = P( t_8_0 > 3.571) = <u>Less than 0.05%</u>

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0
3 years ago
What is the slope between the points (4, 5) and (7, 9)
kifflom [539]

Answer:

m = 4/3

Step-by-step explanation:

5 0
3 years ago
Pldsssssss help<br> ????
Tatiana [17]

Answer:

Roberta's boat started farther from the dock, but John's boat moves more quickly.

Step-by-step explanation:

6 0
3 years ago
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