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natta225 [31]
3 years ago
15

Please help me with Part B! I've already answered Part A.

Mathematics
1 answer:
Lostsunrise [7]3 years ago
4 0

When we multiply our servings by a given amount, we're not multiplying our cost of cake by the same amount. This tells us that this is not proportional. One way to think about proportional relationships, we already said, that the ratio between the variables will be equivalent.

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i got 28cm.... But im not sure

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Find the solution to x2=28
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x² = 28

x = √28

Factoring 28

28 | 2

14 | 2

7 | 7

1

28 = 2.2.7 = 2².7

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x = 2√7

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Is the binomial a factor of the polynomial function?
olchik [2.2K]

Answer:

YES

NO

NO

Step-by-step explanation:

The given polynomial is: $ f(x) =  x^3 + 4x^2 - 25x - 100 $

(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.

To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.

∴ f(5) = 5³ + 4(5)² - 25(5) - 100

        = 125 + 100 - 125 - 100

        = 225 - 225

        = 0

We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.

Now, to check (x + 2) is a factor.

i.e., to check x = - 2 satisfies f(x) or not.

f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100

      = -8 + 16 + 50 - 100

     = -108 + 66

     ≠ 0

Therefore, (x  + 2) is not a factor of f(x).

To check (x - 4) is a factor.

∴ f(4) = 4³ + 4(4)² - 25(4) - 100

        = 64 + 64 - 100 - 100

        = 128 - 200

        ≠ 0

Therefore, (x - 4) is not a factor of f(x).

7 0
3 years ago
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