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Scilla [17]
3 years ago
15

While driving down the road, a grasshopper strikes the windshield of a bus and makes a mess in front of the face of the driver.

This is a good example of Newton's third law of motion. The action is the grasshopper hitting the windshield and the reaction is the windshield stopping the grasshopper. Which of the two forces is greater: the force on the grasshopper or the force on the windshield?
Physics
2 answers:
RideAnS [48]3 years ago
6 0

Answer:

Both forces are equal in magnitude but opposite in direction

Explanation:

As per Newton's law we know that every action has equal and opposite reaction.

So here when grasshopper strikes the wind screen then action force due to grasshopper on wind shield will hit the screen and at the same moment the wind shield will also exert a force on the grasshopper

This force due to windshield on the grasshopper will be same in magnitude but opposite in the direction

So here correct answer will be

The two forces are equal in magnitude

nlexa [21]3 years ago
3 0

Answer:

The force on the grass hopper is equal and opposite to the force on the wind shield.

Explanation:

It is a known fact every action has an equal and opposite reaction. Here the action force is the grasshopper hitting the windshield.

The reaction force is the force exerted by the windshield on the grasshopper.

If the force of windshield on the grasshopper is more, grasshopper would have been thrown away. If the grasshopper's force on the windshield is greater, the windshield would have broken.

But here these constitute equal and opposite action-reaction pair of forces and so the grasshopper is able to repeatedly strike the windshield.

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Answer:

Hypothesis

Explanation:

Refer to a trial solution to a problem as a hypothesis, often called an "educated guess" because it provides a suggested outcome based on the evidence.

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Explanation:

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The ammonia molecule (NH3) has a dipole moment of 5.0×10?30C?m. Ammonia molecules in the gas phase are placed in a uniform elect
Neko [114]

Question (continuation)

(a) What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to E S from parallel to perpendicular?

(b) At what absolute temperature T is the average translational kinetic energy 3/2kT of a molecule equal to the change in potential energy calculated in part (a)?

Answer:

a. 9.0 * 10^-24 Joules

b. 0.44K

Explanation:

Given

Let p = dipole moment = 5.0 * 10^-30 Cm

Let E = Magnitude = 1.8 * 10^6 N/m

a.

The charge in electric potential = Final Charge - Initial Charge

Initial Charge = Potential Energy

Initial Energy = -pE cosФ where Ф = 0

So, initial Energy = - 5.0 * 10^-30 * 1.8 * 10^6

Initial Energy = -9 * 10^-24 Joules

Final Energy = 0

Charge = 0 - (-9.0 * 10^-24)

Charge = 9.0 * 10^-24 Joules

b.

Absolute Temperature

Change in Kinetic Energy = Change in Potential Energy = 9.0 * 10^-24

Change in Kinetic Energy = 3/2kT where k is Steven-Boltzmann constant = 1.38 * 10^-23

So,

9.0 * 10^-24 = 3/2 * 1.38 * 10^-23 * T

T = (9.0 * 10^-24 * 2)/(3 * 1.38 * 10^-23)

T = (18 * 10^-24)/(4.14 * 10^-23)

T = 0.44K

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When a small cart collide with a large mass then during collision they must be in contact with each other for some interval of time

During this contact interval we can say they will exert normal force on each other

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<u><em>They both experience the same magnitude of the collision force.</em></u>

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