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Scilla [17]
3 years ago
15

While driving down the road, a grasshopper strikes the windshield of a bus and makes a mess in front of the face of the driver.

This is a good example of Newton's third law of motion. The action is the grasshopper hitting the windshield and the reaction is the windshield stopping the grasshopper. Which of the two forces is greater: the force on the grasshopper or the force on the windshield?
Physics
2 answers:
RideAnS [48]3 years ago
6 0

Answer:

Both forces are equal in magnitude but opposite in direction

Explanation:

As per Newton's law we know that every action has equal and opposite reaction.

So here when grasshopper strikes the wind screen then action force due to grasshopper on wind shield will hit the screen and at the same moment the wind shield will also exert a force on the grasshopper

This force due to windshield on the grasshopper will be same in magnitude but opposite in the direction

So here correct answer will be

The two forces are equal in magnitude

nlexa [21]3 years ago
3 0

Answer:

The force on the grass hopper is equal and opposite to the force on the wind shield.

Explanation:

It is a known fact every action has an equal and opposite reaction. Here the action force is the grasshopper hitting the windshield.

The reaction force is the force exerted by the windshield on the grasshopper.

If the force of windshield on the grasshopper is more, grasshopper would have been thrown away. If the grasshopper's force on the windshield is greater, the windshield would have broken.

But here these constitute equal and opposite action-reaction pair of forces and so the grasshopper is able to repeatedly strike the windshield.

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My Notes Ask Your Teacher 6. Six blocks with different masses, m, each start from rest at the top of smooth, frictionless inclin
Tresset [83]

Answer:

Kf > Ka = Kb > Kc > Kd > Ke

Explanation:

We can apply

E₀ = E₁

where

E₀: Mechanical energy at the beginning of the motion (top of the incline)

E₁: Mechanical energy at the end (bottom of the incline)

then

K₀ + U₀ = K₁ + U₁

If v₀ = 0  ⇒  K₀

and  h₁ = 0   ⇒    U₁ = 0

we get

U₀ = K₁    

U₀ = m*g*h₀ = K₁

we apply the same equation in each case

a) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

b) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

c) U₀ = K₁ = m*g*h₀ = 35 Kg*9.81 m/s²*4m = 1373.40 J

d) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*16m = 1098.72 J

e) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*4m = 274.68 J

f) U₀ = K₁ = m*g*h₀ = 105 Kg*9.81 m/s²*6m = 6180.30 J

finally, we can say that

Kf > Ka = Kb > Kc > Kd > Ke

8 0
3 years ago
Which of the following is an example of heat convection?
lora16 [44]
I believe it’s a liquid inside a beaker on a hot Bunsen burner (c)

This is because : Everyday Examples of Convection
Boiling water - The heat passes from the burner into the pot, heating the water at the bottom. Then, this hot water rises and cooler water moves down to replace it, causing a circular motion. Radiator - Puts warm air out at the top and draws in cooler air at the bottom.

Not sure if it’s right tho!
8 0
3 years ago
Read 2 more answers
What is the net force acting on the buggy. ?The net force is pointing to the ?
Papessa [141]

Answer: 390, right

explanation: The net force is just the sum of all of these forces acting on an object. ... This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula.

6 0
3 years ago
When you irradiate a metal with light of wavelength 433 nm in an investigation of the photoelectric effect, you discover that a
sergij07 [2.7K]

Answer:

The right solution is:

(a) 2.87 eV

(b) 1.4375 eV

Explanation:

Given:

Wavelength,

= 433 nm

Potential difference,

= 1.43 V

Now,

(a)

The energy of photon will be:

E = \frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}

  = 4.59\times 10^{-19} \ J

or,

  = \frac{4.59\times 10^{-19}}{1.6\times 10^{-19}}

  = 2.87 \ eV

(b)

As we know,

⇒ Vq=\frac{hc}{\lambda}-\Phi_0

By substituting the values, we get

⇒ 1.43\times 1.6\times 10^{19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}-\Phi_0

⇒                       \Phi_0=2.3\times 10^{-19} \ J

or,

⇒                            =\frac{2.3\times 10^{-19}}{1.6\times 10^{-19}}

⇒                            =1.4375 \ eV

5 0
3 years ago
Explain 2 reasons why reactions take place faster at high temperature
Vlada [557]
I have one reason the reaction take place faster because the molecules are going at a faster pace because the temperature is rising 
8 0
3 years ago
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