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Scilla [17]
3 years ago
15

While driving down the road, a grasshopper strikes the windshield of a bus and makes a mess in front of the face of the driver.

This is a good example of Newton's third law of motion. The action is the grasshopper hitting the windshield and the reaction is the windshield stopping the grasshopper. Which of the two forces is greater: the force on the grasshopper or the force on the windshield?
Physics
2 answers:
RideAnS [48]3 years ago
6 0

Answer:

Both forces are equal in magnitude but opposite in direction

Explanation:

As per Newton's law we know that every action has equal and opposite reaction.

So here when grasshopper strikes the wind screen then action force due to grasshopper on wind shield will hit the screen and at the same moment the wind shield will also exert a force on the grasshopper

This force due to windshield on the grasshopper will be same in magnitude but opposite in the direction

So here correct answer will be

The two forces are equal in magnitude

nlexa [21]3 years ago
3 0

Answer:

The force on the grass hopper is equal and opposite to the force on the wind shield.

Explanation:

It is a known fact every action has an equal and opposite reaction. Here the action force is the grasshopper hitting the windshield.

The reaction force is the force exerted by the windshield on the grasshopper.

If the force of windshield on the grasshopper is more, grasshopper would have been thrown away. If the grasshopper's force on the windshield is greater, the windshield would have broken.

But here these constitute equal and opposite action-reaction pair of forces and so the grasshopper is able to repeatedly strike the windshield.

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A slingshot shoots a marble. It travels at an average speed of 15 m/s for 12 seconds before hitting it's target. How far does it
salantis [7]
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2 years ago
A piston-cylinder chamber contains 0.1 m3 of 10 kg R-134a in a saturated liquid-vapor mixture state at 10 °C. It is heated at co
vaieri [72.5K]

Answer:

(A) 10132.5Pa

(B)531kJ of energy

Explanation:

This is an isothermal process. Assuming ideal gas behaviour then the relation P1V1 = P2V2 holds.

Given

m = 10kg = 10000g, V1 = 0.1m³, V2 = 1.0m³

P1 = 101325Pa. M = 102.03g/mol

P2 = P1 × V1 /V2 = 101325 × 0.1 / 1 = 10132.5Pa

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W = 98.01 × 8.314 × 283 ×ln(1.0/0.1)

= 531kJ.

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