The light intensity incident on a metallic surface with a work function of 3 eV produces photoelectrons with a maximum kinetic e
nergy of 2 eV. The frequency of the light is doubled. Determine the maximum kinetic energy (in eV).
1 answer:
Answer:
7ev
Explanation:
The Energy of an incident light is given as E = hf;
Where h is Planks constant
f is frequency
Also.
E = Eo + K.E
Where Eo is work function and K.E is kinetic energy.
Hence substituting the given values,
E = 3ev + 2ev = 5ev
The frequency of the incident wave if it's doubled the Energy would be doubled since E is proportional to f with other elements been constant.
Hence :E = 10ev
But K.E = E -Eo
= 10ev - 3ev = 7ev
Maximum Kinetic Energy is 7ev.
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