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kupik [55]
3 years ago
10

The light intensity incident on a metallic surface with a work function of 3 eV produces photoelectrons with a maximum kinetic e

nergy of 2 eV. The frequency of the light is doubled. Determine the maximum kinetic energy (in eV).
Physics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

7ev

Explanation:

The Energy of an incident light is given as E = hf;

Where h is Planks constant

f is frequency

Also.

E = Eo + K.E

Where Eo is work function and K.E is kinetic energy.

Hence substituting the given values,

E = 3ev + 2ev = 5ev

The frequency of the incident wave if it's doubled the Energy would be doubled since E is proportional to f with other elements been constant.

Hence :E = 10ev

But K.E = E -Eo

= 10ev - 3ev = 7ev

Maximum Kinetic Energy is 7ev.

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The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²

<h3> Magnetic dipole moment of the bar magnet</h3>

The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}

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The complete question is below:

What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.

Learn more about dipole moment here: brainly.com/question/27590192

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Answer: Find the answer in the explanation

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