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3 years ago

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The light intensity incident on a metallic surface with a work function of 3 eV produces photoelectrons with a maximum kinetic e

nergy of 2 eV. The frequency of the light is doubled. Determine the maximum kinetic energy (in eV).

1 answer:

Vlad1618 [11]3 years ago

7 0

Answer:

7ev

Explanation:

The Energy of an incident light is given as E = hf;

Where h is Planks constant

f is frequency

Also.

E = Eo + K.E

Where Eo is work function and K.E is kinetic energy.

Hence substituting the given values,

E = 3ev + 2ev = 5ev

The frequency of the incident wave if it's doubled the Energy would be doubled since E is proportional to f with other elements been constant.

Hence :E = 10ev

But K.E = E -Eo

= 10ev - 3ev = 7ev

Maximum Kinetic Energy is 7ev.

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2 years ago

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The water line from the street to my house is 1 inch diameter and made of PVC (i.e. smooth). The line is roughly 450 ft long. Th

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The right solution is "126 Psi".

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= $896.22\times 10^3 \ Pa$

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According to the question,

Z₁ = 0

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As we know,

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On substituting the values, we get

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2 years ago

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vredina [299]

Answer:

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2 years ago