Answer:
The coefficient of kinetic friction = 0.026
Explanation:
An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N.
Here we have to note that the weight is pulled at a constant speed . This means that the net force acting on the weight is zero.
The external force acting on the body is in the forward direction and the friction acts in the backward direction.
Friction increases as the mass of the body increases.
Friction =
We now equate this to the external force of 15 N.
15 =
=
= 0.026
The coefficient of kinetic friction = 0.026
Answer: 888.45 K or 615.3 °c
Explanation:
According to Gay Lussacs law which states that at constant volume, pressure of an ideal gas is directly proportional to it's absolute temperature.
P/T = Constant
Therefore, P1/T1 = P2/T2
P1 = 6.7 atm
T1= 23°c = 273.15 + 23 = 296.15K
Since P2 is tripled, then,
P2 = 6.7 x 3= 20.1 atm
T2 = (20.1 x 296.15) ÷ 6.7
T2 = 888.45 K
Or in celcius 615.3°c
Answer:
1. s
2. m
3. start m/s
4. end m/s
5. m/s^2
Explanation:
1. t is the suffix for the time and it is related to seconds [s]
2. d is the suffix for distance and it is related to meters [m]
3. Vi is the suffix for the initial velocity and it is related to meters per second [m/s]
4. Vf is the suffix for the final velocity and it is related to meters per second [m/s]
5. a is the suffix for the acceleration and it is related to meters per squared second [m/s^2]
Kinetic energy:
KE= .5 mv^2
KE = .5 * 1000 kg * 3 m’s^2
KE = 4500 kg m^2/s^2
KE = 4500 Joules
Answer:
It should be 1 meter, but I'm no scientist.
Explanation: IDK